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3 years ago

Which of the following sets could be the sides of a right triangle?

Mathematics

1 answer:

o-na [289]3 years ago

4 0

Answer:

1st answer

Step-by-step explanation:

From pythagorus theorem.

Since hypotenuse

$= \sqrt{ {2}^{2} + {3}^{2} }= \sqrt{ {13}}$

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Fill in the blanks to rewrite the given statement. Every positive number has a positive square root.

worty [1.4K]

Answer:

Step-by-step explanation:

Given is a statement that e is a positive number

This can also be written as:

(a) All positive numbers have positive square root.

(b) For every positive number e, there is a square root for e

4 0

3 years ago

NEED HELP CAN SOMEONE ANSWER AND EXPLAIN?

Ipatiy [6.2K]

Answer:

whats the question????

7 0

2 years ago

This is due in an hour please be quick!!

erma4kov [3.2K]

Answer:

106 m^2

Step-by-step explanation:

First multiply the shaded area:

12 * 10 = 120

Then multiply the white space:

7 * 2 = 14

Then subtract the white space from the shaded area to find the area of only the shaded area.

120 - 14 = 106

Final answer: 106 m^2

I hope this helps!

6 0

2 years ago

Read 2 more answers

4 to the 8th power divided by 4 to the 5th power

Natasha2012 [34]

Alright, 4 to the 8th power is 4x4x4x4x4x4x4x4 which ends up as 65,536.

4 to the 5th power is the same thing but with 5 4's and that is 1,024.

All you need to do now is 65,536/1,024 = 64.

Solved! :D

6 0

3 years ago

Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const

Vilka [71]

Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration $a_a$ , we have the following equation of motion

$s/4 = a_at_a^2/2$

where s (m) is the total distance, ta = 3 s is the time

$s = 4a_a3^2/2 = 18a_a$

$a_a = s/18$

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration $a_k$ , we have the following equation of motion:

$s/3 = a_kt_k^2/2$

tk = 4 s is the time

$s = 3a_k4^2/2 = 24a_k$

$a_k = s/24$

Since $a_a = s/18$ we can conclude that $a_a > a_k$ , so Alison would win.

The time it takes for Alison to cover the entire track

$s = a_aT_a^2/2$

$T_a^2 = 2s/a_a = 2s/(s/18) = 36$

$T_a = \sqrt{36} = 6 s$

The time it takes for Kevin to cover the entire track

$s = a_kT_k^2/2$

$T_k^2 = 2s/a_k = 2s/(s/24) = 48$

$T_a = \sqrt{48} = 6.93 s$

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

4 0

3 years ago