I need urgent help and maybe please explain how to do it? I will appreciate it
1 answer:
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Answer:
A hole at x=-4.
Step-by-step explanation:
This is a fraction so we have to worry about division by zero.
The only time we will be dividing by 0 is when x+4 is 0.
Solving the equation
x+4=0 for x:
Subtract 4 on both sides:
x=-4
So there is either a vertical asymptote or a hole at x=-4.
These are the kinds of discontinuities we can have for a rational function.
If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.
If is is a vertical asymptote, x=-4 will make the top NOT zero.
Let's see what -4 for x in x^2+6x+8 gives us:
(-4)^2+6(-4)+8
16+-24+8
-8+8
0
Top and bottom are 0 when x=-4.
Let's see what happens after simplication.
We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.
So what 2 numbers together multiply to be 8 and add up to be 6.
I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.
We we able to cancel out that factor that was giving us x=-4 is a zero.
Therefore there is a hole at x=-4.
Bb = brown hair phenotype
bb = black hair phenotype
we see that B = brown hair is the dominant gene while b = black hair is the recessive gene
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ll = short hair, this is a lowercase L
Ll = long hair
In this case, l = short hair is the recessive gene while L = long hair is the dominant gene.
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Check out the diagram below to see the dihybrid crosses for each of the hair color and hair length genotypes. From there, I show all of the genotypes possible for any offspring. Those genotypes are
- LlBb = long brown hair (comes up 4 times)
- Llbb = long black hair (comes up 4 times)
- llBb = short brown hair (comes up 4 times)
- llbb = short black hair (comes up 4 times)
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If we are talking about 1 offspring, then it is not possible for him/her to have both "long black hair AND short brown hair" as the instructions state. So let's consider two offspring instead.
The probability of having long black hair is 4/16 = 1/4 as there are 4 cases of Llbb out of 16 cases total. Similarly, the probability of getting llBb is 4/16 = 1/4 as well, for pretty much the same reasons.
The probability of having both events occur is (1/4)*(1/4) = 1/16
The multiplication of probabilities is valid because the two events are independent.
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<h3>Final Answer: A) 1/16</h3>