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3 years ago

I need urgent help and maybe please explain how to do it? I will appreciate it

Mathematics

1 answer:

melisa1 [442]3 years ago

4 0

Answer:

It will take 12.5 days for Alejandra to catch up with Javier and they both will have travelled 800m

Step-by-step explanation:

Alejandra "catching up" implies that they will both have travelled the same distance

Therefore,

Let y represent the distance when Alejandra will catch up with Javier

Since both equations have the same y-value (distance):

24x+500 = 12x+650

24x - 12x = 650 - 500

12x = 150

x = 12.5

It will take 12.5 days for Alejandra to catch up with Javier

Next, put the amount of time into any of the 2 equations to find what the distance is:

24x + 500 = y

24 (12.5) + 500 = y

y = 800

800m is the distance travelled when Alejandra catches up with Javier

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Find the value of the trigonometric ratio. Simplify the ratio if possible.

sweet [91]

Step-by-step explanation:

Given that,

BC = 8

Ac = 15

We can find AB using the pythagoas theorem.

$AB=\sqrt{AC^2+BC^2}\\\\=\sqrt{15^2+8^2}\\\\AB=17$

We know that,

$\cos\theta=\dfrac{B}{H}$ , B is base and H is Hypotenuse

$\cosB=\dfrac{8}{17}$

Hence, this is the required solution.

3 0

3 years ago

The moats separating people from the animals are 5 m wide for lions and 4 m wide for the elephants. If the lion’s moat is 4 m de

ZanzabumX [31]

Answer:

The elephants' moat should be 3.2 meters deep.

Step-by-step explanation:

Suppose, the depth of the elephants' moat is $x$ meter.

Width of the lions' moat is 5 meter and width of the elephants' moat is 4 meter.

Given that, the lion’s moat is 4 meter deep.

So, according to the ratio of width and depth, the equation will be.......

$\frac{5}{4}=\frac{4}{x}\\ \\ 5x=4*4\\ \\ 5x=16\\ \\ x=\frac{16}{5}=3.2$

Thus, the elephants' moat should be 3.2 meters deep.

3 0

3 years ago

Help me plzzzzzzzzz :))))

riadik2000 [5.3K]

Marty read 4 times as many pages as Nelson and Jennifer COMBINED. Marty read 1,860 pages.

In total, after dividing Marty's total by 4, Jennifer and Nelson both read a total of 465 pages.

After subtracting Nelson's 240, Jennifer is then found to have read 225 pages.

B would be the best viable option, as it clearly shows that 240+?x4=1,860, which it does.

Hope this helped. Khan Academy is a great resource for any learner. :)

4 0

3 years ago

Read 2 more answers

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

3 years ago

I need to 2,4,6,8 But please send me the work too

Ugo [173]

ok for number 2.) 2+8+1+5+1+3+1+7+5+4+3+1=41 and 41 divided by the number of number which is 12= 3.41666666667

the mean for number 2 is 3.41666666667.

for the median you put the number from least to greatest, like so:

1, 1, 1, 1, 2, 3, 3, 4, 5, 5, 7, 8.

The middle is 3 and 3 so 3+3 divided by 2 is 6 so the median is 6.

I cant do mode but range is 8-1 divided by 2

4 0

3 years ago