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blagie [28]
2 years ago
15

Reverse faults (seen here) are fractures that occur from compression forces that push the earth's crust together. The movement,

indicated by the arrows, along the fault line best illustrates that.
SAT
1 answer:
kotykmax [81]2 years ago
6 0

Answer:

B

Explanation:

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All of the following are effective countermeasures of fatigue except:
FinnZ [79.3K]

All of the following are effective countermeasures of fatigue except: D. Allowing your eyes to lose focus.

<h3>What is a countermeasure?</h3>

This is the term that helps to describe something that helps a person to fight against another thing. The counter measure is usually what is taken in order to prevent something from happening or occurring.

Here fatigue has to do with the fact that a person is tired, worn out and they need to rest well in order to continue functioning properly in the chores or the tasks that they are known to indulge in.

When a person is tired they would have issues with their eyes enabling them to focus on what they are doing.

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2 years ago
The farther a star is away from earth,the more it is ___
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Answer:

the more it is red shifted

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3 years ago
Which effect are children who receive unconditional love most likely to display?.
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They would most likely display better stress resilience
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3. What is the meaning of "radical" as it is used in
kobusy [5.1K]
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3 years ago
the volumes of two similar solids are 210 m3 and 1,680 m3. the surface area of the larger solid is 856 m2. what is the surface a
kolezko [41]

The surface area of the smaller solid is found to be 214 square meters.

<h3>What is Surface area?</h3>

The surface area is given as the sum of the area of all the faces of a three-dimensional object.

The same shape has equivalent ratio of the surface area to volume. It is given as:

\rm \dfrac{\sqrt{area_1}}{\sqrt{area_2}}=\dfrac{\sqrt[3]{Volume_1} }{\sqrt[3]{Volume_2} }

On considering the power of 6 at both the sides of the equation:

\rm \dfrac{area_1^2}{area_2^2}=\dfrac{volume_1}{volume_2}

Considering area 1 and volume 1 for the larger solid, and area 2 and volume 2 for the smaller solid, substituting the values give:

\rm\dfrac{(856\;m^2)^3}{(area_^2)^3}=\dfrac{(1680\;m^3)^2}{(210\;m^3)^2}

By solving the above equation, the area of the smaller solid is found as 214 square meters. Thus, option B is correct.

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2 years ago
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