This is an example of asexual reproduction because the cells are dividing and not binding as with sexual reproduction.
The surface area of the smaller solid is found to be 214 square meters.
<h3>What is Surface area?</h3>
The surface area is given as the sum of the area of all the faces of a three-dimensional object.
The same shape has equivalent ratio of the surface area to volume. It is given as:
![\rm \dfrac{\sqrt{area_1}}{\sqrt{area_2}}=\dfrac{\sqrt[3]{Volume_1} }{\sqrt[3]{Volume_2} }](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B%5Csqrt%7Barea_1%7D%7D%7B%5Csqrt%7Barea_2%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7BVolume_1%7D%20%7D%7B%5Csqrt%5B3%5D%7BVolume_2%7D%20%7D)
On considering the power of 6 at both the sides of the equation:

Considering area 1 and volume 1 for the larger solid, and area 2 and volume 2 for the smaller solid, substituting the values give:

By solving the above equation, the area of the smaller solid is found as 214 square meters. Thus, option B is correct.
Learn more about volume, here:
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Answer:
3.5 K
Explanation:
When a sample of a substance releases heat energy, its temperature decreases according to the equation:

where
Q is the heat energy released
m is the mass of the substance
C is the specific heat capacity
is the initial temperature
is the final temperature
For the block of brass in this problem, we have:
m = 0.1 kg is the mass
Q = -56.4 J is the heat energy released (negative since it is released)
C = 380 J/kg K is the specific heat capacity of brass
is the initial temperature
Solving for
, we find the final temperature:

Answer:
The Hardy Weinberg equation is defined as p squared plus two p Q plus Q Squared equals one, and this equation is used to determine if evolution is occurring in a particular population. So P is defined as the dominant Ulliel frequency and cue is defined as the recess of illegal frequency. So if one of these illegal frequencies is given, we can easily find the frequency value for the other a wheel. So let's say that the dominant frequency, the dominant Ulliel here, is defined as a one. We have another legal called a two, so let's say a one is given. So to find a to all we need to dio so a two frequency would be equal toe one minus a one. And once we have the value of A to we can determine the hetero zegas frequency by solving this part of the equation. So we would just do two times a one times a two, and that would give us the frequency of the hetero Zika's individuals. Okay,
Answer:
sure and the answer is 1.902071808e+13
Explanation: