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mixas84 [53]
2 years ago
5

PLS HELP!!! there are 72 students in a speech contest. yesterday, 1/3 of them gave their speeches. today, 5/6 of the remaining s

tudents gave their speeches. How many students still haven't given their speeches?
Mathematics
2 answers:
Lubov Fominskaja [6]2 years ago
6 0

Answer:

above is the answer to the question

poizon [28]2 years ago
4 0

xedrcftvgyubhijnmkzse

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PLEASE HELP ANSWER THIS ASAP!!! :)
PilotLPTM [1.2K]

Answer:

C, 42 degrees

Step-by-step explanation:

Considering  angle BAD is 60 degrees, that makes angle BCD also 60 degrees. Since parallelograms have 360 degrees in total, we're still missing 240 degrees. Since angles BAD and BCD are congruent (equal), that means that angles ABC and ADC also have to be congruent. To find their angles, we do 240 divided by 2, which equals 120. Now that we know all of the angles, lets focus on angle ADC. Since angle 1 has been given to us, all we need to do is subtract 78 from 120 which turns out to be 42 degrees, which is the answer.

5 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
stepladder [879]
When the direction is reversed  velocity = 0 

v = ds/dt =  6t^2 - 42t + 60 = 0

t^2 - 7t + 10 = 0

(t - 5)(t - 2) = 0

t = 2 s  and 5 s   which are the times when the direction is reversed
Position at t = 2 =  2(2)^3 - 21(2)^2 +60(2) + 3 =  55 feet
  at t = 5  position =  28 feet

Acceleration  = dv/dt = 12t - 42

At t = 2  acceleration =  -18 ft s-2
At  t = 5   ...............    = 18 ft s-2


6 0
3 years ago
The 67 is between which of the following integers?
Vlad1618 [11]

Answer:

8 and 9

Step-by-step explanation:

8² = 64, and 9² = 81. Equivalently, √64 = 8 and √81 = 9. Since 67 is between 64 and 81, √67 must be between 8 and 9.

4 0
3 years ago
How do I solve part b?
Minchanka [31]

Answer:

x \approx 1.4

Step-by-step explanation:

This problem gives one the following equation to model the graph of a line: (y=x^2-2). The problem asks one to find the value of (x) when (y=0). Rather than using the graph, an easier way to solve this problem is to substitute (0) in for the value of (y) and then solve for (x) using inverse operations.

y=x^2-2\\

Substitute,

0=x^2-2

Inverse operations,

0=x^2-2\\\\2=x^2\\\\\sqrt{2}=x

Round:

x \approx 1.4

As one can see on the graph, this result is very close to the value at which the graph intersects the (x) axis. Thus, one can conclude that (x) does indeed approximately equal (1.4)

6 0
2 years ago
Perform the indicated operation. x/x + 1 - 1/x - 1 + 2x/x^2 - 1 =
luda_lava [24]
\frac{x}{x + 1} - \frac{1}{x - 1} + \frac{2x}{x^{2} - 1}
\frac{x}{x + 1} - \frac{1}{x - 1} + \frac{2x}{(x + 1)(x - 1)}
\frac{x(x - 1)}{(x + 1)(x - 1)} - \frac{1(x + 1)}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x}{(x + 1)(x - 1)} - \frac{x + 1}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x + x + 1 + 2x}{(x + 1)(x - 1)}
\frac{x^{2} + 2x + 1}{(x + 1)(x - 1)}
\frac{(x + 1)(x + 1)}{(x + 1)(x - 1)}
\frac{(x + 1)^{2}}{(x + 1)(x - 1)}
\frac{x + 1}{x - 1}
4 0
3 years ago
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