Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
Answer:
3
Step-by-step explanation:
The slope is the coefficient to the x variable.
In the equation y = 3x, this means 3 is the slope because it is the coefficient to x.
So, the slope is equal to 3.
Answer:
f(x)^-1 = 3x-3/x
Step-by-step explanation:
f(x) =-3/x-3
y= -3/x-3
x=-3/y-3
-3= (y-3)x
-3= xy-3x
-xy=-3x + 3
y= -3x +3/x
y= 3x-3/x
f(x)^-1 = 3x-3/x
Answer:
-7 is m
Step-by-step explanation:
-2 - -7 = 5
This is an example
Your length of the rectangle is 2 times the width.
Let length = 2x
Let width = x
Now your area = 450m^2
2x.x = 450 ("." means multiply)
2x^2 = 450
Therefore x^2 = 225
Therefore x= 15
If your x=15 , then you know your width.
Length = 2x (2 x 15 = 30)
Therefore:
Length = 30m
Width = 15m
Hope that helped! :)
