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cestrela7 [59]
3 years ago
11

Solve the following equation. Then place the correct number in the box provided.

Mathematics
1 answer:
Shtirlitz [24]3 years ago
5 0
X=5.
let me know if you need me to show how to do it
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Parker is going to attend a four-year university that has an annual tuition of $16,110. He has $45,800 in savings and has a gran
Svetlanka [38]

Answer:

$13,640

Step-by-step explanation:

money that need to pay for the tuition for all four years

=$16,110×4

=$64,440

the money he had

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the difference

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3 0
3 years ago
Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
What is the number 153 split in half
Bumek [7]
The Answer is 76.5, because 153/2 is 76.5
7 0
3 years ago
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The price of a stove is s dollars. Pedro makes a 10% down payment for a two-year installment purchase. The monthly payment is m
Sever21 [200]

Answer:

0.2

Step-by-step explanation:

8 0
3 years ago
at a sport banquett 8 guests are seated at each of the 15 tables how many guests (x) are seated at the table
Novosadov [1.4K]

Answer:

120

Step-by-step explanation:

15x8=120 so that the answer

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