She is traveling at a constant speed.
The maximum height to which the ball attain before falling back down is 1147.96 m
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Initial velocity (u) = 150 m/s
- Final velocity (v) = 0 m/s (at maximum height)
- Acceleration due to gravity (g) = 9.8 m/s²
- Maximum height (h) =?
<h3>How to determine the maximum height </h3>
The maximum height reached by the ball can be obtained as illustrated below:
v² = u² – 2gh (since the ball is going against gravity)
0² = 150² – (2 × 9.8 × h)
0 = 22500 – 19.6h
Collect like terms
0 – 22500 = –19.6h
–22500 = –19.6h
Divide both side by –19.6
h = –22500 / –19.6
h = 1147.96 m
Thus, the maximum height reached by the ball is 1147.96 m
Learn more about motion under gravity:
brainly.com/question/22719691
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