All categories

3 years ago

What is the potential difference when the current in a circuit is 5mA and resistance is 30 Ohms

Physics

1 answer:

Mashcka [7]3 years ago

4 0

<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf• \: The \: current \: in \: a \: circuit \: is \: 5 \: amps. \: and \: resistance \: is \: 30 \: Ohms.$

$\\$

<h2> $\bf{ \underline{To \: Find :- }}$ </h2>

$\sf{• \: The \: Potential \: Difference. }$

$\\$

$\huge\bf{ \underline{ Solution:- }}$

$\sf According \: to \: the \: question,$

$\sf• \: Current \: (I) = 5 \: Amps.$

$\sf• \: Resistance \: (R) = 30 \: Ω$

$\sf{Potential \: difference \: means \: Voltage \: ( V).}$

$\sf{We \: know \: that, }$

$\bf \red{ \bigstar{ \: V = IR }}$

$\rightarrow \sf V =5 \times 30$

$\rightarrow \sf V =150$

$\\$

$\sf \purple{Therefore, \: the \: potential \: difference \: is \: 150 \: v \: .}$

You might be interested in

Object a and object b are both in motion when they collide with each other. They then continue in a new direction unaffected by

Harrizon [31]

This is an elastic collision

bcuz i think they move apart after the collision

sorry if im wrong

8 0

2 years ago

5. Describe the shape of the waveform in the secondary coil for a sine, square and triangle wave in the primary coil. How does t

Volgvan

Answer:

When primary coil is exited by sin wave,this will result in sin wave in secondary coil as well.According to law,flux induced in the secondary coil will have same waveform as in the primary coil.

5 0

3 years ago

How does mass differ from weight? List 2 differences.

Alinara [238K]

weight is vector vary from place to place

5 0

2 years ago

Read 2 more answers

A 560-g squirrel with a surface area of 930cm2 falls from a 5.0-m tree to the ground. Estimate its terminal velocity. (Use a dra

bija089 [108]

Explanation:

Terminal velocity is given by:

$v_t=\sqrt{\frac{2mg}{\rho C_dA}}$

Here, m is the mass of the falling object, g is the gravitational acceleration, $C_d$ is the drag coefficient, $\rho$ is the fluid density through which the object is falling, and A is the projected area of the object. in this case the projected area is given by:

$A=\frac{A_s}{2}=\frac{930cm^2}{2}=465cm^2\\465cm^2*\frac{1m^2}{10^4cm^2}=0.0465m^2\\560g*\frac{1kg}{10^3g}=0.56kg$

Recall that drag coefficient for a horizontal skydiver is equal to 1 and air density is $1.28\frac{kg}{m^3}$ .

$v_t=\sqrt{\frac{2(0.56kg)(9.8\frac{m}{s^2})}{(1.28\frac{kg}{m^3}(1)(0.0465m^2)}}\\v_t=13.58\frac{m}{s}$

Without drag contribution the motion of the person is an uniformly accelerated motion, thus:

$v_f^2=v_o^2+2gh\\v_f=\sqrt{2gh}\\v_f=\sqrt{2(9.8\frac{m}{s^2})(5m)}\\v_f=9.9\frac{m}{s}$

7 0

2 years ago

10 PTS. If an electromagnetic wave has a frequency of 8 ⋅ 10^14 H z , what is its wavelength? Use λ=V/F. The speed of light is 3

ad-work [718]

Answer :

The wavelength would be 410 m/s

3 0

3 years ago