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2 years ago

HELP ASAP.....NO LINKS & NO TROLLING

Mathematics

1 answer:

AfilCa [17]2 years ago

4 0

Answer:

This is the answer

$(x + 3)(5x + 2) \\ x = - 3 \: \: or \: \: x = - \frac{2}{5}$

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Examine the following system of inequalities.

lubasha [3.4K]

Answer:

Dotted linear inequality shaded above passes through (0, 4) and (4, 0). Solid exponential inequality shaded below passes through (negative 2,2) & (0,5)

Step-by-step explanation:

we have

$y > -x+4$ ----> inequality A

The solution of the inequality A is the shaded area above the dotted line $y=-x+4$

The dotted line passes through the points (0,4) and (4,0) (y and x-intercepts)

and

$y \leq -(1/2)^{x} +6$ -----> inequality B

The solution of the inequality B is the shaded area above the solid line $y=-(1/2)^{x} +6$

The solid line passes through the points (0,5) and (-2,2)

therefore

The solution of the system of inequalities is the shaded area between the dotted line and the solid line

see the attached figure

Dotted linear inequality shaded above passes through (0, 4) and (4, 0). Solid exponential inequality shaded below passes through (negative 2,2) & (0,5)

7 0

3 years ago

Can anyone please solve this

sasho [114]

Answer:

Its ether 3 or 4.

Step-by-step explanation:

its more than likely its 4 but I wasn't %100 sure.

5 0

1 year ago

Which row operation will triangularize this matrix?

Ludmilka [50]

Triangularizing matrix gives the matrix that has only zeroes above or below the main diagonal. To find which option is correct we need to calculate all of them.
In all these options we calculate result and write it into row that is first mentioned:

A)R1-R3
$\left[\begin{array}{ccc}-1&0&0|0\\0&1&1|6\\2&0&1|1\end{array}\right]$

B)2R2-R3
$\left[\begin{array}{ccc}1&0&1|1\\-2&2&1|4\\2&0&1|1\end{array}\right]$

C)-2R1+R3
$\left[\begin{array}{ccc}0&0&-1|-1\\0&1&1|6\\2&0&1|1\end{array}\right]$

D)2R1+R3
$\left[\begin{array}{ccc}4&0&3|3\\0&1&1|6\\2&0&1|1\end{array}\right]$

E)3R1+R3
$\left[\begin{array}{ccc}5&0&4|4\\0&1&1|6\\2&0&1|1\end{array}\right]$

None of the options will triangularize this matrix. The only way to <span>triangularize this matrix is
R3-2R1
</span> $\left[\begin{array}{ccc}1&0&1|1\\0&1&1|6\\0&0&-1|-1\end{array}\right]$
<span>
This equation is similar to C) but in reverse order. Order in which rows are written is important.</span>

4 0

2 years ago

Travis goes to the book fair where paperback books are $1.50 and hardback books are $3. Travis buys five paperback books and two

givi [52]

5x1.50 = 7.5
2x3 = 6

7.5 + 6 = 13.5
Change Travis will recieve
= 20 - 13.5
= $6.5

5 0

2 years ago

56 less than the quotient of a number and 4 is -52

const2013 [10]

X - the number

The algebraic expression:
$\frac{x}{4}-56=-52$

The solution:
$\frac{x}{4}-56=-52 \ \ \ |+56 \\
\frac{x}{4}=4 \ \ \ |\times 4 \\
x=16$

3 0

3 years ago