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3 years ago

HELP ASAP.....NO LINKS & NO TROLLING

Mathematics

1 answer:

AfilCa [17]3 years ago

4 0

Answer:

This is the answer

$(x + 3)(5x + 2) \\ x = - 3 \: \: or \: \: x = - \frac{2}{5}$

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adelina 88 [10]

-#(1(1+#&$:3:+343;2()1-^|•{`}÷~^¢™¢

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3 years ago

The polynomial 6x2 + x - 15 has a factor of 2x - 3. What is the other factor?

PilotLPTM [1.2K]

Hey mate,

I have attached the answer below.

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4 0

3 years ago

Solve the above que no. 55

aleksandr82 [10.1K]

Answer:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

2) $\left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)$ $\tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}$

3) $\left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)$

4) $\left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)$ $\sin^{2}A+\cos^{2}A = 1$

5) $\frac{1}{\sin^{2}A\cdot \cos^{2}A}$

6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

Step-by-step explanation:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

2) $\left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)$ $\tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}$

3) $\left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)$

4) $\left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)$ $\sin^{2}A+\cos^{2}A = 1$

5) $\frac{1}{\sin^{2}A\cdot \cos^{2}A}$

6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

4 0

3 years ago

Help asap plssssssss

kiruha [24]

Answer:

127

Step-by-step explanation:

m<PQR and m<RQS are supplementary angles so their sum is 180

3x - 5 + x + 1 = 180 add like terms

4x - 4 = 180 subtract 4 from both sides

4x = 176 divide both sides by 4

x = 44

m<PQR is 3x - 5 replace x with 44

3*44 - 5 = 127

4 0

3 years ago

Solve for x: -7 < x-1 < 8<br> 06 0-6 >x>9<br> 06 >x>-9<br> O-6

avanturin [10]

Answer:

−

Step-by-step explanation:

7 0

3 years ago