What is the slope of this line? A. -3B. -3/4C. 4D. 3/4

Mathematics

1 answer:

rusak2 [61]2 years ago

6 0

The slope of the line is -3/4, so the answer is B

You might be interested in

What are the zeros of x^2-5x-1

nexus9112 [7]

The zeros is another name for solutions.

x^2 - 5x - 1 = 0

You must use the quadratic formula to find x.

In the formula, a = 1, b = -5 and c = -1.

Plug into formula and solve for x.

The values of x are the zeros of the function.

3 0

3 years ago

Explain the steps on how u got the answer ••••••••••••••••••

dem82 [27]

Answer:

volume of cyclinder=πr²h

=3.14×2²×3=37.68cm³

rectangular prism volume=6×5×7

=210cm³

total volume=37.68+210=247.68cm³

6 0

3 years ago

Read 2 more answers

What are the roots to this quadratic equation?

myrzilka [38]

16x^2=9
x^2=9/18
x=sqrt(9/16)
x=3/4,-3/4
so the root of the quadratic equation are 3/4 and -3/4

5 0

2 years ago

how much would $150 invested at 8% interest compounded anually be worth after 13 years? A(t)=P(1+r/n)^

PIT_PIT [208]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$150\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &13
\end{cases}
\\\\\\
A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589$