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Westkost [7]
2 years ago
11

A two-factor study with 3 levels of factor A and 3 levels of factor B uses a separate sample of 10 participants in each treatmen

t condition. How many participants are needed for the entire study
Mathematics
1 answer:
Alexxx [7]2 years ago
8 0

Answer:

P=60

Step-by-step explanation:

From the question we are told that:

Number of Factor study N=2

Level L=3

Sample size n=10

Generally the umber of participants needed for the study is mathematically given as

 P=N*L*n

 P=2*3*10

 P=60

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William works at a nearby electronics store. He makes a commission of 6% percent on everything he sells. If he sells a computer
Naddika [18.5K]

Commission earned by William is $ 45.84

<h3><u>Solution:</u></h3>

Given that,

William makes a commission of 6% percent on everything he sells

He sells a computer for $764.00

<em><u>To find: Commission amount of William</u></em>

Given that he makes a commission of 6 % on everything he sells. So he has received a commission of 6 % of $ 764.00

Commission amount of William = 6 % of $ 764.00

a % of b can be written in fraction as \frac{a}{100} \times b

6 \% \text { of } 764=\frac{6}{100} \times 764=0.06 \times 764=45.84

Thus commission earned by William is $ 45.84

8 0
3 years ago
Help this is the last question to a test
goblinko [34]
You’re a Horrible Person
Solutions are given in alphabetical order (k, x, y, z)

[(1, 0, 0, 1), (1, 0, 1, 0), (1, 1, 0, 0), (2, 0, 1, 1), (2, 1, 0, 1), (2, 1, 1, 0), (3, 1, 1, 1), (8, 0, 0, 2), (8, 0, 2, 0), (8, 2, 0, 0), (9, 0, 1, 2), (9, 0, 2, 1), (9, 1, 0, 2), (9, 1, 2, 0), (9, 2, 0, 1), (9, 2, 1, 0), (10, 1, 1, 2), (10, 1, 2, 1), (10, 2, 1, 1), (16, 0, 2, 2), (16, 2, 0, 2), (16, 2, 2, 0), (17, 1, 2, 2), (17, 2, 1, 2), (17, 2, 2, 1), (24, 2, 2, 2), (27, 0, 0, 3), (27, 0, 3, 0), (27, 3, 0, 0), (28, 0, 1, 3), (28, 0, 3, 1), (28, 1, 0, 3), (28, 1, 3, 0), (28, 3, 0, 1), (28, 3, 1, 0), (29, 1, 1, 3), (29, 1, 3, 1), (29, 3, 1, 1), (35, 0, 2, 3), (35, 0, 3, 2), (35, 2, 0, 3), (35, 2, 3, 0), (35, 3, 0, 2), (35, 3, 2, 0), (36, 1, 2, 3), (36, 1, 3, 2), (36, 2, 1, 3), (36, 2, 3, 1), (36, 3, 1, 2), (36, 3, 2, 1), (43, 2, 2, 3), (43, 2, 3, 2), (43, 3, 2, 2), (54, 0, 3, 3), (54, 3, 0, 3), (54, 3, 3, 0), (55, 1, 3, 3), (55, 3, 1, 3), (55, 3, 3, 1), (62, 2, 3, 3), (62, 3, 2, 3), (62, 3, 3, 2), (64, 0, 0, 4), (64, 0, 4, 0), (64, 4, 0, 0), (65, 0, 1, 4), (65, 0, 4, 1), (65, 1, 0, 4), (65, 1, 4, 0), (65, 4, 0, 1), (65, 4, 1, 0), (66, 1, 1, 4), (66, 1, 4, 1), (66, 4, 1, 1), (72, 0, 2, 4), (72, 0, 4, 2), (72, 2, 0, 4), (72, 2, 4, 0), (72, 4, 0, 2), (72, 4, 2, 0), (73, 1, 2, 4), (73, 1, 4, 2), (73, 2, 1, 4), (73, 2, 4, 1), (73, 4, 1, 2), (73, 4, 2, 1), (80, 2, 2, 4), (80, 2, 4, 2), (80, 4, 2, 2), (81, 3, 3, 3), (91, 0, 3, 4), (91, 0, 4, 3), (91, 3, 0, 4), (91, 3, 4, 0), (91, 4, 0, 3), (91, 4, 3, 0), (92, 1, 3, 4), (92, 1, 4, 3), (92, 3, 1, 4), (92, 3, 4, 1), (92, 4, 1, 3), (92, 4, 3, 1), (99, 2, 3, 4), (99, 2, 4, 3), (99, 3, 2, 4), (99, 3, 4, 2), (99, 4, 2, 3), (99, 4, 3, 2)]
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3 years ago
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Murljashka [212]

Answer:

The steps are more or less the same, except for one new addition:

1. Divide the tens column dividend by the divisor.

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3. Subtract the product from the divisor.

4. Bring down the dividend in the one's column and repeat it.

Step-by-step explanation:

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2 years ago
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Neporo4naja [7]
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7 0
3 years ago
Ther are 6 girls and 7 boys in a class. A team of 10 players is to be selected from the class. How many different combinations o
Charra [1.4K]

Answer:

13C10 =286

Step-by-step explanation:

To solve this problem we must use the formula of combinations.

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Then we look for  13C10

13C10 =\frac{13!}{10!(13-10)!}

13C10 =\frac{13!}{10!*3!}

13C10 =286

There are 286 possible combinations

6 0
3 years ago
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