All categories

3 years ago

☁️ Math Quiz

Mathematics

2 answers:

just olya [345]3 years ago

3 0

Answer:

³log27 + ²log256

=³log3³ + ²log2⁸

=3 × ³log3 + 8 × ²log2

=3 × 1 + 8 × 1

=3 + 8

=11

Cerrena [4.2K]3 years ago

3 0

Answer:

$\sf{11}$

Step-by-step explanation:

$\sf\log_{3}(27)+\log_{2}(256)$

$\sf=\log_{3}({3}^{3})+\log_{2}({2}^{8})$

$\sf=3\log_{3}(3)+8\log_{2}(2)$

$\sf=3(1)+8(1)$

$\sf=3+8$

$\sf=11$

You might be interested in

which number goes in the blank to make the statement true? 3.098 <..............is it a) 3.089 b) 3.908 c) 2.099 or d) 2.998

densk [106]

La respuesta es la letra b

7 0

4 years ago

Read 2 more answers

Determine the domain and range of (g ○ f)(x) if f of x is equal to 4 over the quantity x squared minus 4 end quantity and g(x) =

lara [203]

The domain and range of a function are the possible x and y values of the function.

The domain and the range of the function is: (a) $\mathbf{D:\{x \in R|x \ne -2,2\}}$ and $\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}$

The functions are given as:

$\mathbf{f(x) = \frac{4}{x^2 - 4}}$

$\mathbf{g(x) = x + 2}$

(g o f)(x) is calculated as:

$\mathbf{(g\ o\ f)(x) = g(f(x))}$

So, we have:

$\mathbf{(g\ o\ f)(x) = \frac{4}{x^2 - 4} + 2}$

Take LCM

$\mathbf{(g\ o\ f)(x) = \frac{4 + 2x^2 - 8}{x^2 - 4} }$

$\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }$

Represent the denominator as follows, to calculate the domain

$\mathbf{x^2 - 4 \ne 0 }$

Add 4 to both sides

$\mathbf{x^2 \ne 4 }$

Take square roots of bot sides

$\mathbf{x \ne \±2 }$

Hence, the domain of the function is:

$\mathbf{D:\{x \in R|x \ne -2,2\}}$

On the graph of $\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }$ (see attachment), the function does not have a value from y = 1 to 2.

Hence, the range is:

$\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}$

Read more about domain and range at:

brainly.com/question/1632425

5 0

2 years ago

Read 2 more answers

Estimate decimals sums and differences

Lady_Fox [76]

First basically solve.
Next, take the number after the decimal point and see if it's larger than 5 or lesser than 4.
Than, Look at the number before the decimal point and relate back to step 2 (Next) if the number is higher than one. Add by 1 to the number before the decimal.
Example:
4.45
vvvv

4.(4)5 > The 4 is lesser than 4, so the number before the decimal point is keep the same.
vvvvvvv
Answer: 4

6 0

4 years ago

Function or not a Function?

iogann1982 [59]

Answer:

not a function

Step-by-step explanation:

the input of K is used more than once

6 0

3 years ago

If f(x) varies directly with x^2, and f(x) = 75 when x = 5, find the value of f(4). A)100 B)50 C)48 D)25

ehidna [41]

That means f(x)=kx²

so
f(5)=75=5²k
solve for k
75=5²k
75=25k
divide by 25
3=k

f(x)=3x² is da equation

so
f(4)=3(4)²
f(4)=3(16)
f(4)=48

C is answer

6 0

4 years ago