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Schach [20]
3 years ago
10

☁️ Math Quiz

Mathematics
2 answers:
just olya [345]3 years ago
3 0

Answer:

³log27 + ²log256

=³log3³ + ²log2⁸

=3 × ³log3 + 8 × ²log2

=3 × 1 + 8 × 1

=3 + 8

=11

Cerrena [4.2K]3 years ago
3 0

Answer:

\sf{11}

Step-by-step explanation:

\sf\log_{3}(27)+\log_{2}(256)

\sf=\log_{3}({3}^{3})+\log_{2}({2}^{8})

\sf=3\log_{3}(3)+8\log_{2}(2)

\sf=3(1)+8(1)

\sf=3+8

\sf=11

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lara [203]

The domain and range of a function are the possible <em>x and y values </em>of the function.

<em>The domain and the range of the function is: (a) </em>\mathbf{D:\{x \in R|x \ne -2,2\}}<em> and </em>\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}<em />

The functions are given as:

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So, we have:

\mathbf{(g\ o\ f)(x) = \frac{4}{x^2 - 4} + 2}

Take LCM

\mathbf{(g\ o\ f)(x) = \frac{4 + 2x^2 - 8}{x^2 - 4} }

\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }

Represent the denominator as follows, to calculate the domain

\mathbf{x^2 - 4 \ne 0 }

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\mathbf{x^2 \ne 4 }

Take square roots of bot sides

\mathbf{x \ne \±2 }

Hence, the domain of the function is:

\mathbf{D:\{x \in R|x \ne -2,2\}}

On the graph of \mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} } (see attachment), the function does not have a value from <em>y = 1 to 2.</em>

Hence, the range is:

\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}

Read more about domain and range at:

brainly.com/question/1632425

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ehidna [41]
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C is answer
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