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Dafna1 [17]
3 years ago
7

Estimate decimals sums and differences

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0
First basically solve.
Next, take the number after the decimal point and see if it's larger than 5 or lesser than 4.
Than, Look at the number before the decimal point and relate back to step 2 (Next) if the number is higher than one. Add by 1 to the number before the decimal.
Example:
4.45
vvvv

4.(4)5 > The 4 is lesser than 4, so the number before the decimal point is keep the same.
vvvvvvv
Answer: 4
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Geometry question for homework.
mars1129 [50]

So remember that the distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} .

1.

\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3

Distance between (4,-5) and (4,-2) is 3 units.

2.

\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.

3 0
3 years ago
So yeah and can you explain how to do it thanks this be a lot of help
Zinaida [17]
Answer: -29a-6b+59c
You need to combine like terms
6 0
3 years ago
Read 2 more answers
Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg
Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) <u>Optimal solution</u>: 40.000 units of R and 10.000 of PC = $17.000

c) <u>Slack variables</u>: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) <u>Binding Constaints</u>:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is  

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.  

3 0
3 years ago
I need help !! Can someone answer this mathematics question for algebra 1. Question number five pls.
Ymorist [56]

Answer:

3x cubed- 3x squared- 11x -22

7 0
2 years ago
Central Allen High School's girls golf team has won 76% of its games this year. The team has won 19 games. How many total games
lawyer [7]

Answer: 25 games

Step-by-step explanation:

Take the fractions 76/100 and 19/x

Cross multiply. 76 times x equally 76x and 100 times 19 equals 1900.

Divide 76x by 76 which equals just x.

Divide 1900 by 76 which equals 25.

x=25

8 0
3 years ago
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