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ratelena [41]
3 years ago
8

What can be concluded about the information on the blueprint of the living room? Check all that apply.

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

hello

Step-by-step explanation:

You might be interested in
Solve the equation. Check your solution.
VladimirAG [237]
-5x/6  + 1=7/18
lowest common multiple=18
-15x+18=7
-15x=7-18
-15x=-11
x=-11/-15=11/15

The solution set is [11/15]

we check it out.
-5(11/15) /6    +  1 =7/18
(-55/15) / 6 +1=7/18
-55/90  +  1=7/18
(-55+90) /90=7/18
35/90=7/18
7/18=7/18
5 0
4 years ago
MULTIPLYING COMPLEX NUMBERS
Elenna [48]

Answer:

(3 - 2i)(4 + 1)

=3(4 + 1 ) +(-2i)(4 + 1)

=3(4 + 1 ) -2i(4 + 1)

=12 + 3 -8i - 2i

= 15 - 10i

5 0
3 years ago
Can someone help with this math problem please
bija089 [108]

Answer:

0.40p-20

Step-by-step explanation:

hope this helps.

5 0
3 years ago
Write 3 numbers that are greater than 543,000 but less than 544,000
nordsb [41]
Here are some, 543,555, 543,123, and 543,369

Hope this helps

7 0
3 years ago
The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1700 vot
lara [203]

Answer:

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

p_v =P(z>2.562)=0.0052  

So the p value obtained was a very low value and using the significance level given \alpha=0.02 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

\hat p=0.66 estimated proportion of voters that favored construction

p_o=0.63 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:  

Null hypothesis:p \leq 0.63  

Alternative hypothesis:p > 0.63  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.562)=0.0052  

So the p value obtained was a very low value and using the significance level given \alpha=0.02 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

7 0
3 years ago
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