Answer:
apparently, 47461 copis. thats wrong calculations..
Step-by-step explanation:
Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>


Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Answer:
I do not know what math curriculum this is I'm sorry
There are three options which are the square roots of 100, and those are C. -10, D. 10, and F. |10|
C: (-10)^2 = -10 * -10 = 100 (- * - = +)
D: 10 * 10 = 100
F: |10| = 10, and 10 * 10 = 100 (these brackets make a negative number positive, and a positive number stays positive)
Answer:
b x 5 = 30
Step-by-step explanation:
This is one of the many correct answers. The reason why is because it shows that the variable is correct. And if you didn’t know what the variable was you could just divide 30 / 5.