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viktelen [127]
2 years ago
15

Anyone have any website ideas I could use for my computing website project? Thank you.

Computers and Technology
2 answers:
nlexa [21]2 years ago
8 0
Yes like keynote yup keynote I use a lot of PowerPoints on keynote Yk
Ludmilka [50]2 years ago
4 0
An idea is a quiz website which has quizzes on that people can do. It should be quite easy (depending on the person).
Hope this helps :)
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In excel what does sidney need to consider when creating formulas
Musya8 [376]
The biggest thing she need to consider are her variables. and the output she will get.
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3 years ago
Who plays warzone im a roze sweat and ill try to carry with loadout
alexira [117]

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2 years ago
3.4 lesson practice quiz edhesive
Marina86 [1]

3.4 lesson practice quiz edhesive :

Write a program to check if user inputs "yellow"

Answer:

In Python:

col = input("Enter Color: ")

if col == "yellow":

   print("True")

else:

   print("False")

Explanation:

This prompts the user for color

col = input("Enter Color: ")

This checks if color is yellow

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   print("True")

If otherwise, this prints false

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5 0
2 years ago
What is a new ransomware program that encrypts your personal files and demands payment for the files' decryption keys? Multiple
frosja888 [35]

Answer: Simple-locker

Explanation:Simple-locker is the program that works on the technique in which it automatically encrypts the data or files and then demand a certain ransom or money from the user for the decryption of that data. It works on the function to gain the ransom or incentive in the financial form.

The decryption can only be carried out in safe way when the victim has the key to decrypted data or file.

5 0
3 years ago
Given a collection of n nuts and a collection of n bolts, arranged in an increasing order of size, give an O(n) time algorithm t
kari74 [83]

Answer:

See explaination

Explanation:

Keep two iterators, i (for nuts array) and j (for bolts array).

while(i < n and j < n) {

if nuts[i] == bolts[j] {

We have a case where sizes match, output/return

}

else if nuts[i] < bolts[j] {

this means that size of nut is smaller than that of bolt and we should go to the next bigger nut, i.e., i+=1

}

else {

this means that size of bolt is smaller than that of nut and we should go to the next bigger bolt, i.e., j+=1

}

}

Since we go to each index in both the array only once, the algorithm take O(n) time.

8 0
3 years ago
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