3x-7y=2 ; 3x=2+7y x=2x+7y/3
Answer:
A
Step-by-step explanation:
x+y=34 (add the seperate hours together to get the total amount of hours)
10x+15y=410 (multiply the money made each hour by the hours worked and add them together to get the amount of money joy made)
Taking into consideration that the interest is compound (yearly)
the amount of money gather through the years can be calculated by
A = P (1+r)^(t)
6000 = 5000 (1.03)^t
t = ln(6000/5000)/ln(1.03) = 6.16 ≈ 7
c. 7 years
Answer:
It will leave the sprinkler at speed of ![v_2=613.87m/sec](https://tex.z-dn.net/?f=v_2%3D613.87m%2Fsec)
Step-by-step explanation:
We have given internal diameter of the garden hose ![d_1=0.740in=1.8796cm](https://tex.z-dn.net/?f=d_1%3D0.740in%3D1.8796cm)
So radius ![r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm](https://tex.z-dn.net/?f=r_1%3D%5Cfrac%7Bd_1%7D%7B2%7D%3D%5Cfrac%7B1.8796%7D%7B2%7D%3D0.9398cm)
So area ![A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2](https://tex.z-dn.net/?f=A_1%3D%5Cpi%20r_1%5E2%3D3.14%5Ctimes%200.9398%5E2%3D2.7733cm%5E2)
Water in the hose has a speed of 4 ft/sec
So ![v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)](https://tex.z-dn.net/?f=v_1%3D4ft%2Fsec%3D121.92cm%2Fsec%28As%5C%201ft%2Fsec%5C%20%3D30.48cm%2Fsec%29)
Number of holes n = 36
Diameter of each hole ![d_2=0.1397cm](https://tex.z-dn.net/?f=d_2%3D0.1397cm)
So radius ![r_2=0.0698cm](https://tex.z-dn.net/?f=r_2%3D0.0698cm)
So area ![A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2](https://tex.z-dn.net/?f=A_2%3D%5Cpi%20r%5E2%3D3.14%5Ctimes%200.0698%5E2%3D0.0153cm%5E2)
From continuity equation
![A_1v_1=nA_2v_2](https://tex.z-dn.net/?f=A_1v_1%3DnA_2v_2)
![2.7733\times 121.92=36\times 0.0153\times v_2](https://tex.z-dn.net/?f=2.7733%5Ctimes%20121.92%3D36%5Ctimes%200.0153%5Ctimes%20v_2)
![v_2=613.87m/sec](https://tex.z-dn.net/?f=v_2%3D613.87m%2Fsec)
Answer:
4
Step-by-step explanation:
Recall a linear function, is a line on a graph made up of an infinite amount of points which satisfy the relationship. That means at x=3 there is a specific point on the line with an output. The value of a function at x=3 asks, what is the output y value for the input x value?
To find it, we locate 3 on the x-axis. We draw a vertical line directly to the line following the grid line. We mark the point on the line. We then draw a horizontal line directly to the y-axis following the grid line. The point we hit on the y-axis is the value of the function.
Here it is 4.