Answer:
a). 18
b). 26%
c). 39
Step-by-step explanation:
Given question is incomplete; here is the complete question attached.
a). In this part we have to calculate the number of the people surveyed who make less than 5 calls.
From the given table,
Number of people surveyed who make less than 5 calls Or 1 - 4 calls = 18
b). Total number of people surveyed = 18 + 11 + 5 + 3 + 2 = 39
Number of people surveyed, make at least 9 calls = 5 + 3 + 2 = 10
Percentage of these people = ![\frac{\text{People who make calls more than 9 calls per day}}{\text{Total number of people surveyed}}\times 100](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BPeople%20who%20make%20calls%20more%20than%209%20calls%20per%20day%7D%7D%7B%5Ctext%7BTotal%20number%20of%20people%20surveyed%7D%7D%5Ctimes%20100)
= ![\frac{10}{39}\times 100](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B39%7D%5Ctimes%20100)
= 25.64%
≈ 26%
c). Total number of people surveyed = 18 + 11 + 5 + 3 + 2 = 39
Answer:
f(1) = 3
Step-by-step explanation:
f(t) = t² - 1t + 3
we want to find f(1)
all we have to do is replace the t's with 1 and evaluate
f(1) = (1)² - 1(1) + 3
evaluate exponent 1² = 1
f(1) = 1 - 1(1) + 3
multiply
f(1) = 1 - 1 + 3
subtract
f(1) = 3
We know that 24 is 160% more than some recommended number, let's call it "x." This means 1.6 times the recommended number equals 24. Therefore, all we need to do is solve for x.
![1.6x=24](https://tex.z-dn.net/?f=%201.6x%3D24%20%20%20)
![x=\frac{24}{1.6}](https://tex.z-dn.net/?f=%20x%3D%5Cfrac%7B24%7D%7B1.6%7D%20)
Make sense?
Formula for are of a rectangle:
A =L * W
1st isolate W
147 = 3W * W
147 = 3W^2
divide 147 by the by 3 on bot sides
29 = W^2
get ride of the square by square rooting on both sides
7 = W
2nd find the perimeter
P = 2(7) + 2(21)
P = 14 + 42
P = 56
Answer:
![f(x)=4x^2](https://tex.z-dn.net/?f=f%28x%29%3D4x%5E2)
Step-by-step explanation:
<u>Quadratic Model</u>
The quadratic function can be expressed in the form:
![f(x)=ax^2+bx+c](https://tex.z-dn.net/?f=f%28x%29%3Dax%5E2%2Bbx%2Bc)
Where a,b, and c are constants to be determined using the points through which the function passes.
We have the points (-2,16) (0,0) (1,4). To find the values of a,b,c we just substitute the values of x and y and solve the system of equations.
Point (0,0):
![f(0)=a*0^2+b*0+c=0](https://tex.z-dn.net/?f=f%280%29%3Da%2A0%5E2%2Bb%2A0%2Bc%3D0)
It follows that
c=0
Point (-2,16):
![f(0)=a*(-2)^2+b*(-2)+c=16](https://tex.z-dn.net/?f=f%280%29%3Da%2A%28-2%29%5E2%2Bb%2A%28-2%29%2Bc%3D16)
Operating:
![a*(4)+b*(-2)+c=16](https://tex.z-dn.net/?f=a%2A%284%29%2Bb%2A%28-2%29%2Bc%3D16)
Since c=0:
![4a-2b=16](https://tex.z-dn.net/?f=4a-2b%3D16)
Divide by 2:
![2a-b=8\qquad\qquad [1]](https://tex.z-dn.net/?f=2a-b%3D8%5Cqquad%5Cqquad%20%5B1%5D)
Point (1,4):
![f(1)=a*(1)^2+b*(1)+c=4](https://tex.z-dn.net/?f=f%281%29%3Da%2A%281%29%5E2%2Bb%2A%281%29%2Bc%3D4)
![a*(1)+b*(1)+c=4](https://tex.z-dn.net/?f=a%2A%281%29%2Bb%2A%281%29%2Bc%3D4)
Since c=0:
![a+b=4\qquad\qquad [2]](https://tex.z-dn.net/?f=a%2Bb%3D4%5Cqquad%5Cqquad%20%5B2%5D)
Adding [1] + [2]:
2a+a=12
3a=12
a=12/3=4
a=4
From [2]
b=4-a
b=4-4=0
b=0
The model is:
![\boxed{f(x)=4x^2}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%3D4x%5E2%7D)