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2 years ago

Divide 240g in the ratio 5:3:4

Mathematics

1 answer:

Hoochie [10]2 years ago

6 0

Answer:

100g : 60g : 80g

Step-by-step explanation:

5+3+4 =12 total parts

(5/12 of 240)

5/12 x 240 = 100g

3/12 x 240 = 60g

4/12 x 240 = 80g

Check:

100g + 60g + 80g = 240g

Hope this helps!

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3 years ago

Number sequences<br> what are the cube numbers after 64 :64,....

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5³ = 125
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3 years ago

Write an equation of the circle with center (-7,4) and radius 11.

olga_2 [115]

Answer: (x+7)^2 + (y-4)^2 = 121 or (x+7)^2 + (y-4)^2 = 11^2

Step-by-step explanation:

Equation of the circle is:

$(x-h)^2+(y-k)^2=r^2$ , which is the center $(h,k)$ and the radius $r^2$

-Place the center (-7,4) and radius 11 onto that equation:

$(x+7)^2+(y-4)^2=121$ (if simplified radius needed)

$(x+7)^2(y-4)^2=11^2$

7 0

3 years ago

Read 2 more answers

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

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3 years ago

Which values of x and y would make the following expression represent a real number? (4 + 5i)(x + yi) x = 4, y = 5 x = –4, y = 0

Svetllana [295]

Answer:It’s C

Step-by-step explanation: Edge 2020

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2 years ago

Read 2 more answers

Divide 240g in the ratio 5:3:4​

Divide 240g in the ratio 5:3:4