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ratelena [41]
3 years ago
13

In a collision, a 5 kg mass moving at 2m/s transfers all of its momentum to a 1 kg mass. What is the velocity of the 1kg mass af

ter the collision?
Will give brainliest
Mathematics
2 answers:
statuscvo [17]3 years ago
6 0
Answer:
velocity = 10 m/sec in the same direction as the first body did

Explanation:
The momentum of the body can be calculated as follows:
momentum = mass * velocity

For the first body, we have:
mass = 5 kg
velocity = 2 m/sec
momentum = mass * velocity
momentum = 5 * 2 = 10 kg.m/sec

We know that this momentum is transferred completely to the second body

For the second bode, we have:
momentum = 10 Kg.m/sec
mass = 1 kg
momentum = mass * velocity
10 = 1 * velocity 
velocity = 10/1
velocity = 10 m/sec

Finally, we should get the direction of the motion:
Both the velocity of the first and second bodies have positive values. Therefore, the second body is moving in the same direction as the first body did.

Hope this helps :)
Len [333]3 years ago
5 0

Answer:

3.67m/s

Step-by-step explanation:

According to the law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of momentum of bodies after collision. This bodies moves with a common velocity after collision.

Momentum = mass × velocity

For the 5kg ball with velocity of 2m/s;

Its momentum = 5×2 = 10kgm/s²

For the 1kg body;

It's momentum = 10kgm/s (since the 5kg mass transfers all of its momentum to a 1 kg mass.)

Momentum after collision of the bodies will give;

Momentum = (5kg+1kg)v where v is their common velocity.

Momentum after collision = 6v

Using the law of conservation of momentum;

10+10 = 6v

20 = 6v

v = 20/6

v = 3.67m/s

Since both masses have the same velocity after collision, the velocity of the 1kg mass after the collision will also be 3.67m/s

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A recent study focused on the number of times men and women send a Twitter message in a day. The information is summarized below
jok3333 [9.3K]

Answer:

The value of the test statistic = 2.58

Test statistic Z = - 4.805

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

There is  significant difference between in the mean number of times men and women send a Twitter message in a day

Step-by-step explanation:

Step(i):-

Sample size of men  n₁ = 25

mean of the first sample x₁⁻ = 20

Standard deviation of the first sample σ₁ = 5

Sample size of women n₂ = 30

mean of the second sample x₂⁻ = 30

Standard deviation of the first sample σ₂ = 10

Level of significance ∝= 0.01

<u>Step(ii)</u>:-

Null Hypothesis : H₀: There is no significant difference between in the mean number of times men and women send a Twitter message in a day

Alternative Hypothesis :H₁:There is  significant difference between in the mean number of times men and women send a Twitter message in a day

Test statistic

Z = \frac{x^{-} _{1} - x^{-} _{2} }{\sqrt{\frac{S.D_{1} ^{2} }{n_{1} }+\frac{ S.D_{2} ^{2}}{n_{2} }  } }

Z = \frac{20 - 30 }{\sqrt{\frac{(5)^{2}  }{25 }+\frac{ (10)^{2}  }{ 30}  } }

Z =  \frac{-10}{2.081} = - 4.805

The value of the test statistic = 2.58 C

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

<u>Conclusion:</u>-

There is  significant difference between in the mean number of times men and women send a Twitter message in a day

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