25% of the class likes mint gum, 5% likes orange, 20% likes raspberry lemonade, of the remaining % likes cherry. how much is the remaining % of students?
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
72.14 units
Step-by-step explanation:
Let A(8,13), B(5,-18),C(-6,-6) and D(-2,-5)
Apply the distance formula as;

Finding the lengths of the segments
For AB

For BC

For CD

For DA

Finding the perimeter will be;
31.14+16.28+4.12+20.6=72.14 units
The answer is c. I chose the answer c because y=5/2x(I think you forgot to put the x in the question) filled in with the numbers are true while a, b, and d aren't true if filled with 10 and 4.