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lana66690 [7]
4 years ago
9

Which expressions are equivalent to the one below. Check all that apply. 16^x

Mathematics
1 answer:
madam [21]4 years ago
3 0

A.\ 4^x\cdot4^x=4^{x+x}=4^{2x}\qquad\text{used}\ a^n\cdot a^m=a^{n+m}\\\\B.\ 4^{2x}=(4^2)^x=16^x\qquad\text{used}\ (a^n)^m=a^{nm}\\\\C.\ 4^2\cdot4^x=4^{2+x}\\\\D.\ (4\cdot4)^x=16^x\\\\E.\ 4\cdot4^{2x}=4^{1+2x}\\\\F.\ 4\cdot4^x=4^{1+x}\\\\Answer:\ \boxed{B.\ and\ D.}

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Answer:

Step-by-step explanation:

I think the attached photo supports for your question

Here is my anser:

We need to find the slope of the of and from the graph, we see that if x increases from 2 to 4, y decreases from 4 to -2.  Thus, the slope of the blue line is : \frac{-2-4}{4-2} = -3

But the slope of the perpend. bisector of the blue line is the negative reciprocal of -3, or  m= 1/3.

Let's find the slope-intercept form of this bisector.  We need to determine b in y=mx+b.  Referring to the midpoint of the blue line, x= 3; y= 1; and m=1/3.  Then

y=mx+b becomes 1=(1/3)(3) + b.  Solving for b:  1=1+b.  Then b=0.

Thus, the equation of the perpendicular bisector of the blue line through (3,1) is  y=mx + b, or y=(1/3)x + 0, or y=x/3.

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Part B:
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Cost when hiring a lorry to travel 300 miles is 150 pounds
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