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hichkok12 [17]
3 years ago
13

Karen measured an Orange and a tangerine. The orange Weighed 3/4 pounds. The tangerine weighed 4/6 pounds.which was heavier? Wri

te an inequality to show how their weights compare
Mathematics
2 answers:
evablogger [386]3 years ago
8 0
18/24>16/24, the orange is heavier
LenaWriter [7]3 years ago
3 0
Solutions 

Karen measured an Orange and a tangerine. The orange Weighed 3/4 pounds. The tangerine weighed 4/6 pounds. To solve the problem we first have to make the denominators common. To make the <span>denominators common you have to multiply by the GCF ( greatest common factor). 
</span>
4/6 and <span>3/4's common denominator is 24 
</span>
\frac{4}{6} = \frac{16}{24} 


\frac{3}{4} = \frac{18}{24}

18/24>16/24, the orange is heavier
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Convert 13pi/6 to a degree measure <br><br> A=390<br> B=2450.44<br> C=30<br> D=780
Burka [1]

Answer:

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Step-by-step explanation:

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3 years ago
For the following pair of functions, find (f+g)(x) and (f-g)(x).
ch4aika [34]

Given:

The functions are

f(x)=4x^2+7x-5

g(x)=-9x^2+4x-13

To find:

The functions (f+g)(x) and (f-g)(x).

Solution:

We know that,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x^2+7x-5-9x^2+4x-13

(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)

(f+g)(x)=-5x^2+11x-18

And,

(f-g)(x)=f(x)-g(x)

(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)

(f+g)(x)=4x^2+7x-5+9x^2-4x+13

(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)

(f-g)(x)=13x^2+3x+8

Therefore, the required functions are (f+g)(x)=-5x^2+11x-18

and (f-g)(x)=13x^2+3x+8.

7 0
3 years ago
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sukhopar [10]

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Step-by-step explanation:

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increase = 166 - 135 = 31, hence

percent increase = \frac{31}{135} × 100% = 22.96 ≈ 23% → D


4 0
3 years ago
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