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2 years ago

What is 8 3/4 ÷ 2 7/8 (show ur work)

Mathematics

2 answers:

xxMikexx [17]2 years ago

6 0

Answer:

see below:-

Step-by-step explanation:

$\displaystyle{8 \frac{3}{4} \div 2 \frac{7}{8} }$

Convert the mixed fractions into improper fractions.

$\displaystyle{ \frac{8 \times 4 + 3}{4} \div \frac{8 \times 2 + 7}{8} }$

$\displaystyle{ \frac{32 + 3}{4} \div \frac{16 + 7}{8} }$

$\displaystyle{ \frac{35}{4} \div \frac{23}{8} }$

$\displaystyle{ \frac{35}{4} \times \frac{8}{23} }$

$\displaystyle{ \frac{35}{ \cancel4} \times \frac{ \cancel8 {}^{2} }{23} }$

$\displaystyle{ \frac{35 \times 2}{23} }$

$\displaystyle{ \frac{70}{23} }$

$\displaystyle{3 \frac{1}{23} }$

Nadusha1986 [10]2 years ago

4 0

70/23 or 3 1/23

Turn 8 3/4 and 2 7/8 into an improper fraction
35/4 and 23/8
Copy past flip
35/4 x 8/23= 280/92
And then simply 70/23 or 3 1/23

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The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

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$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

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