That's 5 integers...
Logic tells me that a number divided by 5 should be equal to -3. -15/5 is in fact equal to -3.
Let's find 5 integers (two positive and three negative) when added up together equal -15.
-14, -3, -3, 2, 3.
[(-14)+(-3)+(-3)+2+3]/5 = (-15)/5 = -3
Mean = -3
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Now let's put these numbers in order, from lowest to highest - then pick out the middle value...
-14, -3, [-3], 2, 3
The median turns out to be -3.
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Let's look at the numbers once again...
-14, -3, -3, 2, 3
It turns out that -3 appears the most, therefore -3 is the mode too.
2x + 21 = 35
hope this helps
1/2 = 8/16 . . . so there are (<u><em>8</em></u>) - 1/16 pounds servings of chocolate in a 1/2 pound chocolate bar
Answer:
4
Step-by-step explanation:
x = root under 5/2
so it is real and irrational number
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
