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AleksAgata [21]
2 years ago
9

PLEASE HELP LOLL aaaaahhh i’ll give u brainliest!

Mathematics
2 answers:
Nimfa-mama [501]2 years ago
6 0
2 for the first box, 5 for the second, and 7 for the third.
RSB [31]2 years ago
6 0
2 for the first box,5 for second, and 7 for the third
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A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s
wel

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

3 0
3 years ago
₦550 FREE GIFT, SIGN UP TO GET ! https://opay.ng/s/2I0H​
Musya8 [376]

Answer:

ok

Step-by-step explanation:

6 0
3 years ago
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Help plz : 4x-2(x-3)=10+(-9)
Dominik [7]
Distribute -2(x - 3)

4x - 2x + 6 = 10 + -9

Simplify

2x = -5

x = -2.5
7 0
3 years ago
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Juan ordered 20 pizzas for a party.
MakcuM [25]

Answer:

100% of the pizzas have 12 slices or 8 slices

(20x.45x8) + (20x.55x12) = total slices

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3 years ago
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To win at LOTTO in one​ state, one must correctly select 4 numbers from a collection of 50 numbers​ (1 through 50​). The order i
Oksana_A [137]

Answer:

230,300 different selections.

Step-by-step explanation:

If the order does not matter, the number of possible different selections is determined as the combination of choosing four numbers out of 50:

n=\frac{50!}{(50-4)!4!}\\\\n=\frac{50*49*48*47}{4*3*2*1} \\\\n=230,300\ combinations

There are 230,300 possible different selections.

4 0
3 years ago
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