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3 years ago

When solving a linear system by substitution, how do you decide which variable to solve first?

Mathematics

1 answer:

rosijanka [135]3 years ago

7 0

Answer: whichever one is easiest to get by itself.

Step-by-step explanation:

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Factor the following: 2x2+9x+9

ryzh [129]

Answer: (2x+3)(x+3)

Step-by-step explanation:

Looking at this, you know that it must look something like

(? +3)(?+3) , because they must multiply to 9. The ?s must multiply to 2x^2, the most plausible values being 2x and x, ending us up with (2x+3)(x+3)

8 0

3 years ago

Read 2 more answers

-7/10+7/15+1/-20+-9/10+11/15+11/-20 what is the answer please help me .....!!!!

Nat2105 [25]

Answer:

-1

Step-by-step explanation:

-7/10+7/15+1/-20+-9/10+11/15+11/-20

= -7/10 + -9/10 + 7/15 + 11/15 + 1/-20 + 11/-20

= -16/10 + 18/15 + 12/-20

= -8/5 + 6/5 + -3/5

= (-8+6-3)/5

= -5/5

= -1

7 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

3 years ago

Greatest to least 1.202, 1.29, 1.02

Lady bird [3.3K]

If you were to list these numbers in order from greatest to least, it would be 1.29, 1.202, 1.02.
Hope this helps!!

7 0

3 years ago

The data is shown below:

Marina CMI [18]

Answer: 72

Step-by-step explanation: Its in the middle

4 0

3 years ago

When solving a linear system by substitution, how do you decide which variable to solve first?￼

When solving a linear system by substitution, how do you decide which variable to solve first?