Figure this out as though no digits are present. You can choose 8 of the 26 letters and that's it.
26^8 [you can allow repeating letters] = 2.088 * 10^11
The total number of ways that can be chosen with letters and digits intermixed = 36^8
The probability of getting no numbers is 26^8 / 36^8 or (26/36)^8 = 0.07402
So the probability that there were be at least one digit is
1 - 0.07402 = 0.92598
Answer:
405 Problems
Step-by-step explanation:
- One student in class has 15 problems.
- There are 27 students in the class.
Let's <u>multiply</u> 15 by 27.
<em>In all, there would be 405 problems assigned to the whole class.</em>
$3,427 because you take 149000 and multiply by .023 for 2.3%.
Answer:
54.5
Step-by-step explanation:
