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cluponka [151]
3 years ago
9

Find the 20th term in the sequence, where the first term is -2 and the common ratio is-2.

Mathematics
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

Step-by-step explanation:

(1)

a1=-2

r=-2

a_{20}=(-2)(-2)^{20-1}=-2(-2)^{19}=2^{20}=1048576\\(2)\\a_{1}=1000\\r=\frac{200}{1000} =\frac{1}{5} \\a_{8}=1000(\frac{1}{5} )^{8-1}=1000(.2)^7=0.0128\\(3)\\a_{1}=2\\a_{3}=50\\a_{2}=\sqrt{2*50} =10\\r=\frac{10}{2} =5

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andrew11 [14]

Answer:

<u>1/20 of the patrons at Joe's restaurant are expected to be male and out of town.</u>

Step-by-step explanation:

1. Let's review all the information provided for solving this question:

Proportion of patrons that are male at Joe's restaurant = 1/4

Proportion of patrons that are from out of town at Joe's restaurant = 1/5

2.  What  proportion would you expect to be  male and out of town?

For finding the proportion of the patrons, that would be male and that would be from out of town, we do this calculation:

Proportion of patrons that are male at Joe's restaurant * Proportion of patrons that are from out of town at Joe's restaurant

<u>1/4 * 1/5 = 1/20 </u>

<u>It means that 1/20 of the patrons at Joe's restaurant are expected to be male and out of town.</u>

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3 years ago
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IceJOKER [234]
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6 0
3 years ago
2x+2+2x-17=180 what's x?
Alik [6]

Answer:

x= 48.75

Step-by-step explanation:

Add like terms

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3 0
3 years ago
Read 2 more answers
Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)
marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}

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2 years ago
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