All categories

3 years ago

2.8 m 3 m What is the area of this triangle

Mathematics

1 answer:

vlada-n [284]3 years ago

4 0

I think the answer is 7.6m

You might be interested in

PLEASE HURRY

Flura [38]

I hv no idea about this one sorry

7 0

3 years ago

Read 2 more answers

What is the median of 60 57 53 78 44 51 please help and thank u

maksim [4K]

To find the median cancel out numbers on both sides, until one is left in the middle and if there are two in the middle add them up and divide by two.

So in this case the median is
53+78
131 / 2
65.5

8 0

3 years ago

Read 2 more answers

(a) 127.5 is what percent of 51 ?

ExtremeBDS [4]

To solve this, you need to divide 127.5 by 51:
127.5/51 = 2.5
To find the percent, multiply 2.5 by 100:
2.5 x 100% = 250%
So 127.5 is 250% of 51

8 0

4 years ago

Is 4.53 a real number? yes or no

Gennadij [26K]

Answer:

yur

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Sixty percent of the eligible voting residents of a certain community support the incumbent candidate. If eight of the residents

il63 [147K]

By the binomial theorem we know that

$1 = (.4 + .6)^8 \\ = {8 \choose 0} (.4)^{8} (.6)^{0} + {8 \choose 1} (.4)^{7} (.6)^{1} +{8 \choose 2} (.4)^{6} (.6)^{2} + {8 \choose 3} (.4)^{5} (.6)^{3} + {8 \choose 4} (.4)^{4} (.6)^{4} \\ + \quad {8 \choose 5} (.4)^{3} (.6)^{5} + {8 \choose 6} (.4)^{2} (.6)^{6} + {8 \choose 7} (.4)^{1} (.6)^{7} + {8 \choose 8} (.4)^{0} (.6)^{8}$

The probability that exactly 5 of 8 support the incumbent is the term

${8 \choose 5} (.4)^{3} (.6)^{5}$

So at least five of eight support is the sum of this term and beyond,

$p={8 \choose 5} (.4)^{3} (.6)^{5} + {8 \choose 6} (.4)^{2} (.6)^{6} + {8 \choose 7} (.4)^{1} (.6)^{7} + {8 \choose 8} (.4)^{0} (.6)^{8}$

No particularly easy way of calculating that except popping it into Wolfram Alpha which reports

$p = \dfrac{ 46413}{78125}$

Shouldn't half the terms work out to .6 ? Interestingly it's not exactly .6 but pretty close at .594.

6 0

4 years ago