Question

P(A)=0.22 and P(B)=0.46 Find P(A OR B)

Answer 1

In general, the probability of a disjunction is

$P(A \lor B) = P(A)+P(B)-P(A\cap B)$

In this case, A and B are mutually exclusive, so $P(A\cap B)=0$

This simplifies the formula to

$P(A \lor B) = P(A)+P(B) = 0.22+0.46 = 0.68$