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irinina [24]
2 years ago
6

Solve the equation. -4.6p - 6.3p + 3.9= -9.18

Mathematics
2 answers:
Advocard [28]2 years ago
8 0

Answer:

I got u

Step-by-step explanation:

start by adding together -4.6p and 6.3p to get 1.7p. rewrite the equation as 1.7p + 3.9 = -9.18 then subtract 3.9 on both sides to get 1.7p= -13.08 then divide that by 1.7 and p= -7.6

im not 100% sure so im sorry if its wrong

KiRa [710]2 years ago
4 0

Answer: P=1.2

Step-by-step explanation:

-4.6p-6.3p+3.9=-9.18

simplify

-10.9p+3.9=-9.18

-10.9p=-13.08

p=1.2

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What is the value of x<br> What is the value of the exterior angle
Oduvanchick [21]

Answer:

???????

Step-by-step explanation:

triangles add to 180 degrees

lets call the unknown angle y

82 + x + y = 180

we also know that y + (2x-20 ) = 180  because it is a straight line

lets solve this for y

y + (2x-20 ) = 180

subtract (2x-20) from each side

y = 180 - (2x-20)

y = 180 - 2x + 20

y = 200 -2x

substitute this in the triangle equation

82 + x + y = 180

82 + x + 200 -2x = 180

combine like terms

282 -x = 180

subtract 282 from each side

-x = -102

multiply by -1 on each side

x = 102

the exterior angle is 2x-20

exterior angle is 2(102) -20

exterior angle is 204-20

exterior angle is 184

This is impossible.


There is a mistake with this problem

The triangle is not a triangle.  Angle y would be negative. y=-4

6 0
3 years ago
Sarah is a computer engineer and manager and works for a software company. She receives a
daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = a

Given that:

a_4=129\\a_{10}=207

Formula for n^{th} term of an Arithmetic Progression is given as:

a_n=a+(n-1)d

Where d will represent the number of projects increased every year.

and n is the year number.

a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)

Subtracting (2) from (1):

78 = 6d\\\Rightarrow d =13

By equation (1):

129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90

<em>Number of projects in the first year = 90</em>

<em></em>

<em>b) </em>

Number of projects in the twelfth year =

a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233

Each project pays $500

Earnings in the twelfth year = 233 \times 500 = $116500

Sum of an AP is given as:

S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 \times 1938 = $969000

8 0
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Harlamova29_29 [7]

is there a option for all of them?

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3 years ago
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during a 500-meter race, a runner ran the first 400 meters in 1 minute and 25 seconds.she finished the race i 2 minutes and 15 s
mart [117]

She ran the last 100 meters in 2:15 -1:25 = 0:50, so her average speed was

... (100 m)/(50 s) = 2.0 m/s

6 0
3 years ago
PLEASE HELP ME REALLY REALLT REALLY FAST AND SHOW YOUR WORK
insens350 [35]

Answer: 27

Step-by-step explanation:

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3 years ago
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