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3 years ago

students can buy up to 10 books at the book fair the cost of the books as shown in the graph what is the domain of the graph

Mathematics

2 answers:

Rzqust [24]3 years ago

7 0

The correct answer is B

german3 years ago

5 0

The answer is 8 okay

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What is the median of the following numbers?<br> 6,4, 1,9,3,8,3,5, 10

Sergeu [11.5K]

Median = 5

Mean = 5.4444444444444

Mode: 3

Range = 9

Minimum = 1

Maximum = 10

How to find Median:

Arrange your numbers in numerical order. Then the second step is to have an odd number, divide by 2 and round up to get the position of the median number. The last step is to find the even number and if you have it, divide it by 2.

Answer: 5

Hope this helps.

3 0

3 years ago

2/3 (6y - 4) = - 4y <br>

Nookie1986 [14]

Answer:

y = 1/3

Step-by-step explanation:

2/3 (6y - 4) = - 4y

2(6y-4)/3 = -4y

2(6y-4) = (-3)(4y)

y = 1/3

7 0

3 years ago

Read 2 more answers

2/5 x 6/7= I cant figure out this question.

telo118 [61]

Answer:

I got 0.3428571429

Step-by-step explanation:

I got it by inputting (2/5)*(6/7) into my calculator, but if you need more let me know

4 0

2 years ago

Read 2 more answers

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

3 years ago

A rectangular sandbox is surrounded on all sides by a strip of grass that is 5 ft wide on all sides. The length of the sandbox i

kaheart [24]

Answer:

Dimensions:

Length = 13.256m

width = 9.256m

Step-by-step explanation:

Let the length of the sandbox be = l and its width be = w

The length of the sandbox is 4 ft more than the width.

This means that $l = 4 + w$ ----- equation 1

For the next step, we will be assuming that the strip of grass is a perfect rectangle. The length of the grass strip will be equals to the length of the sandbox.

Area of the grass = length X width = $(4 +w) \times 5= 5(4+w)$ ------ equation 2

The total area for the sandbox and the grass is 189 square feet.

This means that

$(w \times (4+w)) + 5(4+w)=189\\w^2+4w+20+5w=189\\w^2+9w-169=0\\w=9.256m$

<em>(Kindly note that the positive value for the width was chosen as length cannot be negative).</em>

Now that we have our width, we can put this into equation 1 to get the length.

$l=9.256+4=13.256m$

7 0

3 years ago