Answer:
Grades 6 and 8
Step-by-step explanation:
If the relationship of girls to boys in two different grades are proportional, <u>they must have the same ratio</u>. To tackle this problem, we can find the <u>ratios</u> of genders in each grade and compare them.
Step 1, finding ratios:
Finding ratios is just like <u>simplifying fractions</u>. We will reduce the numbers by their<u> greatest common factors</u>.




<u>Can't be simplified!</u>
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Step 2:
Notice how grades 6 and 8 both had a ratio of 3:4. We can conclude that these two grades have a proportional relationship between girls and boys.
<em>I hope this helps! Let me know if you have any questions :)</em>
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59 is an outlier it's not in the 70s
Using pythagorean's theorem
a^2+b^2=c^2
a being 3
b being 4
we'll get
9+16=25
where 5 is the hypotenuse and also c.
c^2 = 5^2
the answer is 16 because .80 times 20 is 16
Let's say that B makes $100.
Then A makes $75.
So, your question then becomes 100 is what percent of 75?
This can be solved by setting up the proportion 100 / 75 = x / 100
75x = 10000
x = 133.3
So, B's income is 33.3% more than A's income.