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2 years ago

How do i solve (3c^2d^4) ^3 x (2c^5d^8)^3?

Mathematics

1 answer:

vredina [299]2 years ago

7 0

Answer:

$216c^{21}d^{36}$

Step-by-step explanation:

$(3c^2d^4)^3 * (2x^5d^8)^3$

$(3c^2)^3 (d^4)^3 * (2c^5)^3 (d^8)^3$

$27c^6 d^{12} * 8c^{15} d^{24}$

$216c^{21}d^{36}$

Hope this helps!

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The number of child tickets sold was 75 and the number of adult tickets sold was 97

Step-by-step explanation:

<u><em>The correct question is</em></u>

At the movie theater child admission is $6.30 an adult admission is $9.60 on Wednesday 172 tickets were sold for a total sales of $1403.70 How many child tickets and adult tickets were sold that day?

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see the attached figure

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3 years ago

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Leona [35]

Answer:

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<img src="https://tex.z-dn.net/?f=%28sinx%5E%7B2%7D%20theta%29%5Cfrac%7Bx%7D%7By%7D%281%2Bcostheata%29" id="TexFormula1" title="

beks73 [17]

The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Read more about trigonometry expressions at:

brainly.com/question/8120556

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