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1 year ago

How do i solve (3c^2d^4) ^3 x (2c^5d^8)^3?

Mathematics

1 answer:

vredina [299]1 year ago

7 0

Answer:

$216c^{21}d^{36}$

Step-by-step explanation:

$(3c^2d^4)^3 * (2x^5d^8)^3$

$(3c^2)^3 (d^4)^3 * (2c^5)^3 (d^8)^3$

$27c^6 d^{12} * 8c^{15} d^{24}$

$216c^{21}d^{36}$

Hope this helps!

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Really need need help on this please

Alexxx [7]

Answer:

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Step-by-step explanation:

$\frac{12-3y}{2} + y (\frac{2y-4}{y})$

we substitute the value of "y" in the equation:

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3 years ago

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Nimfa-mama [501]

Remember you can do anything to an equation as long as you do it to both sides
a=age

500 reduced by 2 times a is equal to 388

500-2a=388
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2 years ago

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3 years ago

Solve the system of linear equations by substitution.<br> 2x-y=3<br> x+5y=14

Arturiano [62]

Answer:

x= 29/11 or y= 25/11

Step-by-step explanation:

2x - y= 3 ...........equation 1

x + 5y= 14 ............equation 2

Make x the subject of the formula in equation 2

x= 14 - 5y ..............equation 3

Substitute x=14 - 5y in equation 1

2(14- 5y) - y=3

28 - 10y - y=3

Collect like terms

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divide both sides by coefficient of y

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