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notka56 [123]
3 years ago
8

I’m a group of 55 people 33 are coffee drinkers, 12 are tea drinkers. Assuming that no one in this group drinks both tea and cof

fee, what is the probability that a person piked random from the group does not drink tea or coffee
Mathematics
2 answers:
Scilla [17]3 years ago
5 0
10/55 of the people do not drink coffee or tea.
tester [92]3 years ago
4 0
33+12 = 45 drink either tea or coffee (but not both)

55 - 45 = 10 people drink neither

Divide 10 over 55 and we get 10/55 = 2/11

Use a calculator to find that 2/11 = 0.1818 approximately which converts to 18.18% when you move the decimal point over 2 spots to the right

-------------------------------------------------

Answer as a fraction = 2/11
Answer in decimal form = 0.1818 (approximate)
Answer as a percentage = 18.18% (approximate)<span />
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3 0
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brainly.com/question/12188410

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