Construct a circle with a radius of 8cm, and draw an equilateral triangle inside it. Make sure the length of each side measures
1 answer:
Answer:
<u>Diagram 1</u>
Draw a circle with a radius of 8 cm, ensuring you have clearly marked the center point (black circle with center C1)
Add a point on the circumference of the circle (point C2)
Draw a second circle of radius 8cm with point C2 as its center (red circle with center C2).
<u>Diagram 2</u>
The red circle intersects the black circle at two points (D and E).
Connect these 2 points of intersection with a line segment.
<u>Diagram 3</u>
Draw a third circle with center D and radius DE (shown in blue)
This circle intersects the black circle at point F.
<u>Diagram 4</u>
Draw 2 line segments to connect points D and E with point F - this is your equilateral triangle inside the circle!
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Answer:
A) See attached for graph.
B) (-3, 0) (0, 0) (18, 0)
C) (-3, 0) ∪ [3, 18)
Step-by-step explanation:
Piecewise functions have <u>multiple pieces</u> of curves/lines where each piece corresponds to its definition over an <u>interval</u>.
Given piecewise function:
Therefore, the function has two definitions:
When <u>graphing</u> piecewise functions:
- Use an open circle where the value of x is <u>not included</u> in the interval.
- Use a closed circle where the value of x is <u>included</u> in the interval.
- Use an arrow to show that the function <u>continues indefinitely</u>.
<u>First piece of function</u>
Substitute the endpoint of the interval into the corresponding function:
Place an open circle at point (3, 0).
Graph the cubic curve, adding an arrow at the other endpoint to show it continues indefinitely as x → -∞.
<u>Second piece of function</u>
Substitute the endpoint of the interval into the corresponding function:
Place an closed circle at point (3, 2).
Graph the curve, adding an arrow at the other endpoint to show it continues indefinitely as x → ∞.
See attached for graph.
<h3><u>Part B</u></h3>The x-intercepts are where the curve crosses the x-axis, so when y = 0.
Set the <u>first piece</u> of the function to zero and solve for x:
Therefore, as x < 3, the x-intercepts are (-3, 0) and (0, 0) for the first piece.
Set the <u>second piece</u> to zero and solve for x:
Therefore, the x-intercept for the second piece is (18, 0).
So the x-intercepts for the piecewise function are (-3, 0), (0, 0) and (18, 0).
<h3><u>Part C</u></h3>From the graph from part A, and the calculated x-intercepts from part B, the function g(x) is positive between the intervals -3 < x < 0 and 3 ≤ x < 18.
Interval notation: (-3, 0) ∪ [3, 18)
Learn more about piecewise functions here:
