Answer:
<u>Diagram 1</u>
Draw a circle with a radius of 8 cm, ensuring you have clearly marked the center point (black circle with center C1)
Add a point on the circumference of the circle (point C2)
Draw a second circle of radius 8cm with point C2 as its center (red circle with center C2).
<u>Diagram 2</u>
The red circle intersects the black circle at two points (D and E).
Connect these 2 points of intersection with a line segment.
<u>Diagram 3</u>
Draw a third circle with center D and radius DE (shown in blue)
This circle intersects the black circle at point F.
<u>Diagram 4</u>
Draw 2 line segments to connect points D and E with point F - this is your equilateral triangle inside the circle!
Answer:
Step-by-step explanation:
1) In this question we've been given "a", the leading coefficient. and two roots:
2) There's a theorem, called the Irrational Theorem Root that states:
If one root is in this form then its conjugate
. is also a root of this polynomial.
Therefore
3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then: