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julia-pushkina [17]
2 years ago
5

Use prime factors to determine the HFC of 90 and 126​

Mathematics
2 answers:
Gala2k [10]2 years ago
6 0
Highest common prime factor is three

ohaa [14]2 years ago
6 0

Answer:

Step-by-step explanation:

Comment

The question means that you are to break both numbers down in to prime factors. When you do, what do the numbers have in common

90: 2 * 3 * 3 * 5

126: 2 * 3 * 3 * 7

The bolded numbers are the primes in common

Primes in common (answer): 2 * 3 * 3 = 18

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Isaiah is starting his own gardening business. Isaiah thinks he can charge $15.50 per hour. If he knows he
Genrish500 [490]

Answer:

About $1627.5

Step-by-step explanation:

15.50 x 35 = 542.5

542.5 x 3 (the amount of weeks in a month) = $1627.5

7 0
3 years ago
A jewelry store is selling a set of 4 pairs of gemstone earrings for $58, including tax. Neva and three of her friends want to b
Mnenie [13.5K]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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4 0
3 years ago
-10=-15+5x heeeeeeeeeeeeeeeeeeeeeeelp me
Allisa [31]
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6 0
3 years ago
A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th
morpeh [17]
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
6 0
3 years ago
HELP!!! Simplify cos^2 0 -1/ 4sin^2 0?
Shkiper50 [21]

We need to simpify the given expression. The given expression to us is ,

<u>Given </u><u>Expression</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta }

<u>Using </u><u>Identity</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \red{ sin^2\theta + cos^2\theta = 1}

<u>So </u><u>that</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies - sin^2\theta = cos^2\theta -1

<u>We </u><u>have</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta } \\\\\sf\implies\dfrac{ - sin^2\theta}{4sin^2\theta}=\boxed{\sf -\dfrac{1}{4}}

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>-</u><u>1</u><u>/</u><u>4</u><u>. </u>

5 0
3 years ago
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