Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer:
40.1 cm²
Step-by-step explanation:
V (rectangular prism) = Base area x Height
441 = BA x 11
BA = 441 / 11 = 40.1
11:12 is the answer to your question
Answer:
68%
Step-by-step explanation:
= 68%
I hope this helps!
