1.<AFC
2.<AFD
3.<AFE
4.<AFB
#5, 6 and 7
m<BAE = 59
m<BAC + m<CAD + m<DAE = m<BAE
4x - 20 + x + 12 + x + 1 = 59
6x - 7 = 59
6x = 59 + 7
6x = 66
x = 11
m<BAC = 4x - 20 = 4(11) - 20 = 24
m<CAD = x + 12 = 11 + 12 = 23
m<BAE = x + 1 = 11 + 1 = 12
answer
5.
m<BAC = 24
6.
m<CAD = 23
7.
m<BAE = 12
#8, 9 and 10
m<BAE = 130
m<BAC + m<CAD + m<DAE = m<BAE
3x - 10 + 2x + 5 + x + 15 = 130
6x + 10 = 130
6x = 120
x = 20
m<BAC = 3x - 10 = 3(20) - 10 = 60 -10 = 50
m<CAD = 2x + 5 = 2(20) + 5 = 40 + 5 = 45
m<DAE = x + 5 = 20 + 15 = 35
answer
8.
m<BAC = 50
9.
m<CAD = 45
10.
m<DAE = 35
Answer:
The answer is 20
Step-by-step explanation:
From the graph it shows that J is located at point 15, and Q is located at point 35
If we move 20 units from point J to point Q, we land at point Q, making it the distance they are from one another.
Answer: 2x+8=12, 5x+4=29
Step-by-step explanation:
2x2=4+8=12
5x5=25+4=29
<h3>
Answer: 51 square inches</h3>
=======================================================
Explanation:
There are a few ways to do this. One way is to divide the figure as shown in the diagram below. I divided it into a rectangle and a triangle. Find the area of the rectangle and triangle, then add up those areas to get the final answer.
A = area of rectangle
A = length*width
A = 7*6
A = 42
B = area of triangle
B = 0.5*base*height
B = 0.5*(6-3)*(13-7)
B = 0.5*3*6
B = 1.5*6
B = 9
C = total area
C = A+B
C = 42+9
C = 51 square inches
