What is algebraic expression for a number increased by 13 is 1,989.

Mathematics

2 answers:

SpyIntel [72]2 years ago

7 0

Let the variable n represent the unknown number

Start with n

$\tt \longrightarrow \: n$

Increased by 13 means add 13 to it

$\tt \longrightarrow \: n + 13$

Is 1989 means it equals 1989

$\tt \longrightarrow \: n + 13 = 1989$

➪ Thus, The final equation is (n+13=1989)

White raven [17]2 years ago

4 0

Answer:

expression: x + 13 = 1989

explanation:

Let the number be x

so when this number is increased " + " by 13, it equals to 1989

processing:

x + 13 = 1989

x = 1989 - 13

x = 1976

The number is 1976.

The algebraic equation used: x + 13 = 1989

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3 years ago

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$