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grin007 [14]
3 years ago
15

Question#1 please. Thankyou

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
5 0
The area of a rectangle is L x W, so 9(5+x) is the formula for the area in factored form. It can be simplified to 45+9x
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A bag with 8 marbles is shown below. (2 marbles are yellow, 3 are red, and 3 are blue.) A marble is chosen from the bag at rando
Andreas93 [3]

Answer:

\frac{5}{8}

Step-by-step explanation:

Hi there!

We're given that there are 8 marbles in total. 2 marbles are yellow and 3 are red, making the number of red AND yellow marbles 5 (2+3=5)

Because 5 out of the 8 marbles are yellow or red, the probability of choosing one of them is \frac{5}{8}.

I hope this helps!

7 0
3 years ago
Read 2 more answers
What is 19,067 divided by 43
OlgaM077 [116]

Answer:

443.418604651

Step-by-step explanation:

Thank you for the points!

3 0
3 years ago
Clarance has a 25% off coupon for a tune-up at Quick Service Auto Repair. If a tune-up is regularly $50, what is the sale price?
zvonat [6]

Answer:

$37.50

Step-by-step explanation:

50*.25=12.50

Take $50 - 12.50  = 37.50

7 0
3 years ago
Which expression is equivalent to 4 over 9 (2n - 3)
AlexFokin [52]

Answer:

The result for this equation is \frac{8}{9}n - \frac{4}{3} .

Step-by-step explanation:

-Solve:

\frac{4}{9} (2n-3)

-Multiply 2n and -3 by \frac{4}{9} :

\frac{8}{9} + \frac{-12}{9}

-Reduce \frac{-12}{9} to the lowest term by extracting and canceling out 3:

\frac{8}{9}n - \frac{4}{3}

-So, the result is \frac{8}{9}n - \frac{4}{3} .

3 0
3 years ago
what are two practical products you could add to find 990 x 37 ; 297 693 2970 6930 69300 6330 29700
VMariaS [17]
First evaluate 990 x 37.
990 x 37 = 36630

Test the given numbers to find the pair that adds up to 36630.
Test 297.
The missing pair will be
36630 - 297 = 36333
Will not work

Test 693.
36630 - 693 = 35937
Will not work

Test 2970.
36630 - 2970 = 33660
Will not work

Test 6930
36630 - 6930 = 29700
This works, because 6930 + 29700 = 36630.

Answer: 6930 and 29700.


8 0
3 years ago
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