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Arisa [49]
3 years ago
7

Estimate the area of the irregular shape. Explain your method and show your work

Mathematics
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

20 cm2 is the answer brooooooooooo

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The ratio of green apples to red apples at a grocery store is 2 to 3. There are 78 red apples at the grocery store. What is the
Talja [164]

Answer:

52

Step-by-step explanation:

78 divided by 3 is 26

26 times 2 is 52

3 0
3 years ago
A taxi cab charges $0.55 per mile in addition to a $1.75 flat rate fee. Susie has $10 to spend on a taxi cab ride. The taxi driv
Olenka [21]
The taxi driver doesn't give anyone a ride unless it's 2 miles away, as such you need to add at least $0.55x2 in addition to the $1.75 at the start
1.75+(0.55x2)=2.85
As Susie only has 10 dollars to spend, she can't exceed that. So Susie must spend more than $2.85(minimum from the taxi) and less than $10(her money)
so,
$2.85<Susie<$10
6 0
3 years ago
Let g be the function given by g(x) = the integral from 0 to x sin(t^2) for -1 &lt; or equal to x &lt; or equal to 3. Find the i
grin007 [14]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2841990

_______________


•  According to what is given,

\mathsf{g(x)=\displaystyle\int_0^x sin(t^2)\,dt\qquad\qquad(-1\le x\le 3)}


•  Now, differentiate g by using the Fundamental Theorem of Calculus:

\mathsf{\displaystyle g'(x)=\frac{d}{dx}\int_0^x sin(t^2)\,dt}\\\\\\&#10;\mathsf{\displaystyle g'(x)=sin(x^2)}


<span>•  </span>g is increasing in the interval where g'(x) is positive. So now, just solve this inequality:

\mathsf{g'(x)\ \textgreater \ 0}\\\\&#10;\mathsf{sin(x^2)\ \textgreater \ 0}


•  The sine function is positive for angles that lie either in the first or the second quadrant. So,

\mathsf{0\ \textless \ x^2\ \textless \ \pi}


•  The inequality above involves only non-negative terms. So, the sign of the inequality keeps the same for the square root of those terms:

\mathsf{0\ \textless \ x\ \textless \ \sqrt{\pi}\qquad\quad(i)}


•  Checking the intersection between the interval we just found above and the domain of g:

Notice that

-1\le 0\ \textless \ x\ \textless \ \sqrt{\pi}\le 3


which implies that

\mathsf{\left]0,\,\sqrt{\pi}\right[\subset [1,\,3]}\\\\&#10;\mathsf{\left]0,\,\sqrt{\pi}\right[\subset Dom(g)}.


Therefore,

g is increasing on the interval  \mathsf{\left]0,\,\sqrt{\pi}\right[.}


I hope this helps. =)


Tags:  <em>derivative fundamental theorem of calculus increasing interval differential integral calculus</em>

8 0
3 years ago
What is the height of the tree to the nearest tenth of a foot?
Ugo [173]

Answer:

The height of the tree is approximately 21.4 feet

Step-by-step explanation:

We list out the question parameters first as follows;

The distance from the base of the tree where the angle of elevation is measured, d = 10 feet

The angle of elevation to the top of the tree from 10 feet from the base, θ = 65°

Let 'h' represent the height of the tree, then we have;

The line formed by the angle 65° angle, the height of the tree, 'h', and the distance 'd', form a right triangle with 'h' being the opposite leg to the given reference angle, 65°, and 'd' being the adjacent leg

By trigonometric ratio, we have;

tan(\theta) = \dfrac{Opposite \ leg \ length}{Adjacent\ leg \ length} = \dfrac{h}{d}

∴ h = d × tan(θ)

Plugging in the given values, we get;

h = 10 feet × tan(65°) = 21 feet 5\frac{11}{32} inches

∴  By rounding to the nearest tenth of a foot, the height of the tree, h ≈ 21.4 feet.

3 0
3 years ago
What 3.999 rounded to the nearest tenths
fenix001 [56]
4000 that's a weird one
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7 0
4 years ago
Read 2 more answers
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