What is the height of the tree to the nearest tenth of a foot?
1 answer:
Answer:
The height of the tree is approximately 21.4 feet
Step-by-step explanation:
We list out the question parameters first as follows;
The distance from the base of the tree where the angle of elevation is measured, d = 10 feet
The angle of elevation to the top of the tree from 10 feet from the base, θ = 65°
Let 'h' represent the height of the tree, then we have;
The line formed by the angle 65° angle, the height of the tree, 'h', and the distance 'd', form a right triangle with 'h' being the opposite leg to the given reference angle, 65°, and 'd' being the adjacent leg
By trigonometric ratio, we have;
∴ h = d × tan(θ)
Plugging in the given values, we get;
h = 10 feet × tan(65°) = 21 feet inches
∴ By rounding to the nearest tenth of a foot, the height of the tree, h ≈ 21.4 feet.
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Answer:
Statement A is correct about Sam's box and whisker plot.
Step-by-step explanation:
We have been given a box plot and we are asked to find out true statement according to the box plot.
Since we know data represented by box plot is divided in four equal parts.
Upon looking at our box plot we can see that our data is symmetric. It's median is 15, which means half the math assignments have less than 15 problems and half of the math assignments have more than 15 problems.
Interquartile range represents 50% values of data and it is the difference between upper quartile and lower quartile. IQR is not affected by outliers.
Upon substituting given values from box plot we get,
From IQR we can conclude that half of the assignments contained 15 problems or fewer.Therefore, option A is the correct choice.
<h3>Solution :</h3>
Distance between first tree and last tree is 140m .
And distance between each tree (d) = 5 m
let's solve for number of trees (n) :
hence, total number of trees = 29.