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2 years ago

HELP ME I NEED TO GRAPH THIS ASAP

Mathematics

2 answers:

IceJOKER [234]2 years ago

7 0

Take 2 points

(0,3)
(2,0)

Slope:-

$\\ \rm\Rrightarrow m=\dfrac{0-3}{2-0}=\dfrac{-3}{2}$

Equation of line in point slope form

$\\ \rm\Rrightarrow y-3=-3/2x$

$\\ \rm\Rrightarrow y=-3/2x+3$

Nezavi [6.7K]2 years ago

5 0

Answer:

f(x)=-3/2x+3

Step-by-step explanation:

y intercept is 3, slope is -3/2

f(x)=-3/2x+3

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Louise spins the spinner twice. which probabilities are correct? check all that apply. p(both green) = one-sixteenth p(both blue

Anettt [7]

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2 years ago

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umka21 [38]

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4 years ago

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Triangle ABC has vertices A(- 3, - 4), B(16, - 2) and C(13, - 10) . Show algebraically that ABC is a right angled triangle.

8_murik_8 [283]

Given:

The vertices of a triangle ABC are A(-3,-4), B(16,-2) and C(13,-10).

To show:

That the triangle ABC is a right angled triangle.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The vertices of a triangle ABC are A(-3,-4), B(16,-2) and C(13,-10).

Using the distance formula, we get

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Similarly,

$BC=\sqrt{\left(13-16\right)^2+\left(-10-\left(-2\right)\right)^2}$

$BC=\sqrt{73}$

And,

$AC=\sqrt{\left(13-\left(-3\right)\right)^2+\left(-10-\left(-4\right)\right)^2}$

$AC=\sqrt{292}$

Now, add the square of two smaller sides.

$BC^2+AC^2=(\sqrt{73})^2+(\sqrt{292})^2$

$BC^2+AC^2=73+292$

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Hence proved.

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3 years ago

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zhuklara [117]

100 x 37= 3700

-Agarvated

(Please do not comment anyone who is commenting rudely thank you!)

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4 years ago

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