$\bf \begin{cases} f(x)=&g(x+1)\\ f(3)=&g(3+1)\\ &g(4)\\[-0.5em] \hrulefill& \hrulefill\\ g(x)=&x^2\\ g(4)=&4^2\\ &16 \end{cases}\qquad \qquad f(3)\implies g(4)\implies 16$

8 0

3 years ago

If f and g are functions of time, and at time t = 2, f equals 5 and is rising at a rate of 6 units per second, and g equals 7 an

Yuliya22 [10]

Answer:

f/g at t =3 will be 9/8

d/ddx(f(x)/g(x))=f'(x)d(x)-f(x)g'(x)/(g'(x))^2

rate of change=(6*8)+(9*9)/9^2

rate of change =43/27=1.5925

8 0

3 years ago

Read 2 more answers

7. The diagram shows a regular pentagon inscribed inside the rectangle. Find the values of x, y, and z.

Wewaii [24]

<span>regular pentagon sum of interior = (5 - 2) x 180 = 3 x 180 = 540
so
x = 540 / 5 = 108

180 - 108 = 72
y = 72/2 = 36

z = 180 - 90 - 36
z = 54

answer
x = 108, y = 36 and z = 54</span>

3 0

4 years ago