Question

In an experiment, 200.00 grams of Al2O3 was decomposed producing 77.18 grams of Al. Calculate the percent yield for this experiment?

Answer 1

Answer:

approximately 106 grams

Explanation:

The molecular mass of Aluminum Oxide is approximately 102 grams per mole.

2×Al=

2×27=54

3×O=3×16=48

54+48=102

200

102

=1.96 moles

There are two atoms of Aluminum in one mole and each atom has a mass of approximately 27 grams so

Mass of Al = 1.96×2×27=106 grams

Explanation:

Answer 2

Answer:

Explanation:

Molecular weight of Al: 27

Molecular weight of O: 16

Percentage composition of Al by weight in Al2O3

= (27*2) / (27*2 + 16*3)

= 0.5294

In 200 grams of Al2O3, there are

= 200*0.5294

= 105.88 grams of Al

77.18 grams of Al was produced in the experiment.

Percent yield for the experiment

= product mass / reactant mass * 100%

= 77.18 / 105.88 * 100%

= 72.89%