Answer:
True
Explanation:
Hydrogen bonding is a bond that exists between hydrogen and a highly electronegative element such as oxygen, nitrogen, fluorine etc.
The greater solubility of the triphenylphosphine oxide owes to the hydrogen bonded interaction between it and the 1-propanol.
The alkene lacks such hydrogen bonded interaction because it does not have a highly electronegative atom in its structure.
Hence, triphenylphosphine oxide is removed based on its polarity and hydrogen bonding ability.
There are several different kinds of indicator electrodes. Several metals, such as silver, copper, lead, cadmium, and mercury, will participate in a reversible electron exchange and can serve as indicator electrodes for their ions.
Answer:
C) a halohydrin
Explanation:
In organic chemistry, a halohydrin is a compound whereby halogen and hydroxyl functional groups are bonded to adjacent carbon atoms in the molecule. Halohydrins are formed from alkenes such as cyclohexene in this case.
NBS is a very suitable alternative to Br2 in the synthesis of a halohydrin. Recall that the reactive intermediate when bromine reacts with an alkene is the brominium ion which is a three atom ring ion. If excess water is used as the solvent, then the water attacks the brominium ion to yield the product halohaydrin with trans a trans stereochemistry.
3.85 x 10^24 C atoms x 1 mole/ 6.022x 10^23 atoms = 6.39 Moles C
Transition metals seem to have fairly even levels of reactivity though it seems they to react more with bases than acids. If I didn’t know from the lessons, I would say alkali and alkaline earth metals weren’t very reactive.
(That's my answer when I did a lab about the reaction of metals for chemistry at least.)
