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2 years ago

Can someone help me with this problem?

Mathematics

1 answer:

dlinn [17]2 years ago

8 0

Answer

7 or 4

because do you see how v is lined 2 I don't remember if you times or divide .I'm going to go with times.

So what is 2 x 10 since V=10

2 x 10=20

Then we are going to divide so what is 20 divided by 5 since e=5

20 divided by 5=4

Next our last step what is 4 + 3=7 and there's are answer.

The answer is divide then this would be the answer.

so V(10) divided by 2=5 divided by e(5) =1 + 3=4

Hope this helps have a great day

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Suppose that y varies inversely as x, and x=9 when y=15. Find the value for k and write the function. Group of answer choices La

Radda [10]

Answer:

see explanation

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition that x = 9 when y = 15

15 = $\frac{k}{9}$ ( multiply both sides by 9 )

k = 135

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3 years ago

Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)

melamori03 [73]

Answer:

Step-by-step explanation:

Given that:

$f_x = \dfrac{x^2}{a^7-x^7}$

$= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}$

$= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}$

since $\Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)$

Then, it implies that:

$\implies \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}$

$\mathbf{= \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}$

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2 years ago

Someone please help!!!

scZoUnD [109]

Answer:

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Step-by-step explanation:

45% of 100 is 45

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2 years ago

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3 years ago

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olchik [2.2K]

Hello from MrBillDoesmath!

Answer: "Distributive Property", the second bullet point from the top of the list

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